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aksik [14]
3 years ago
8

If y is 2.5 when x is 5 and y varies directly with x, find y when x is 10.

Mathematics
2 answers:
adoni [48]3 years ago
8 0
Y=2.5 when X=5
Y=5 when X=10

Basically 10÷5=2 so 2.5×2=5
mamaluj [8]3 years ago
3 0

Answer:

The value of y is 5.

Step-by-step explanation:

We have been given that y varies directly with x. Thus, we have

y=kx

Now, y is 2.5 when x is 5. Thus, we have

2.5=k(5)

Divide both sides by 5, we get

k=0.5

Now, we have to find y when x is 10.

y=0.5\times10\\\\y=5

Therefore, the value of y is 5.

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Divide 6 divided by 3/5 <br><br><br> Answer only if u know please:)
meriva

Answer:

The answer is 10 or 10/1

3 0
3 years ago
part of the river she observed fell 1.68 millimeters per year for 1.5 years. Use the distributive property to calculate the exac
Alecsey [184]
1.68 mm per year for 1.5 years could be rewritten as 
(2.00-0.32) mm per year for 1.5 yrs.

Multiply:  (1.5 yrs)(2.00-0.32)(mm/yr) = 3 mm + 0.48 mm = 3.48 mm

This approach makes use of the distributive property of multiplication.
8 0
3 years ago
Suppose that y varies directly as the square of x, and that y=567 when x=9. What is y when x=4
Gwar [14]

Answer:

y  = 112

Step-by-step explanation:

If  y varies directly as the square of x

mathematically;

y ∝ x²

y = kx² where 'k' is the constant of proportionality

let u know the value of k for this equation by making k the subject of the formular from y = kx²

divide both sides by x²

k = y / x²

given that  y = 567 x = 9

k = 567/(9)²

k = 567/81

k = 7

now to get the value of  y when x = 4

from the equation conneting x, y,

y = kx²

y = 7 × (4)²

y = 7 × 16

y  = 112

6 0
3 years ago
Describe the sampling distribution of p(hat). Assume the size of the population is 30,000.
Naya [18.7K]

Answer:

a) \mathbf{\mu_ \hat p = 0.6}

b) \mathbf{\sigma_p =0.01732}

Step-by-step explanation:

Given that:

population mean \mu = 30,000

sample size n = 800

population proportion p = 0.6

a)

The mean of the the sampling distribution is equal to the population proportion.

\mu_ \hat p =  p

\mathbf{\mu_ \hat p = 0.6}

b)

The standard deviation of the sampling distribution can be estimated by using the formula:

\sigma_p = \sqrt{\dfrac{p(1-p)}{n}}

\sigma_p = \sqrt{\dfrac{0.6(1-0.6)}{800}}

\sigma_p = \sqrt{\dfrac{0.6(0.4)}{800}}

\sigma_p = \sqrt{\dfrac{0.24}{800}}

\sigma_p = \sqrt{3 \times 10^{-4}}

\mathbf{\sigma_p =0.01732}

7 0
3 years ago
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ryzh [129]
Ain't nobody got time fo dat (drawing number lines)

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4-1/2=4-1/2
3 and 1/2=3 and 1/2
7 0
3 years ago
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