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Olenka [21]
4 years ago
14

The area of a rectangle is 12.65 m^2. the length measures 5.5 m. what is the width of the rectangle?

Mathematics
2 answers:
gayaneshka [121]4 years ago
6 0

Step-by-step explanation:

area \: of \: rectangle = length  \times width \\  \therefore \: 12.65 = 5.5\times width \\ \\  \therefore \:width =  \frac{12.65}{5.5}  \\  \\ \therefore \:width = 2.3 \: m

Hence, width of rectangle is 2.3 m.

Nat2105 [25]4 years ago
4 0

Answer:

The width of the rectangle is 2.3 m

Step-by-step explanation:

Now, when we are asked to find the area of the rectangle, we will use the formula: Area= length * width. We should be given with at least two values, and then we can use the above formula and can find the third variable.

Now, we are given that the area of a rectangle is 12.65 m^2 and the length measures 5.5 m

So the width is given as:

Area= length * width\\\Rightarrow 12.56= 5.5 * width\\\Rightarrow width= \frac{12.56}{5.5}\\\Rightarrow width=2.3 ~m

So this is the required with of the rectangle.

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See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

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And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

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So then we can conclude that the set X is linearly dependent.

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Therefore 220 adult tickets and 80 children's tickets were sold.
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