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3 years ago

1) Slope = 3; contains (5, 14) 2) What is the answer for this? Help please

Mathematics

1 answer:

MArishka [77]3 years ago

7 0

Answer:

The equation of the line with slope = 3 and point (5, 14)

will be:

$y=3x-1$

Step-by-step explanation:

Given

slope = m = 3

point = (5, 14)

As the point-slope form of the equation of the line is

$y-y_1=m\left(x-x_1\right)$

where m is the slope.

substituting the values m = 3 and the point (5, 14)

$y-14=3\left(x-5\right)$

Add 14 to both sides

$y-14+14=3\left(x-5\right)+14$

$y=3x-1$

Therefore, the equation of the line with slope = 3 and point (5, 14)

will be:

$y=3x-1$

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3 years ago

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1) lets get rid of the parentheses, we dont really need them:

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3 0

3 years ago

Read 2 more answers

How many solutions does this system have?<br> X+ 5y = 0<br> 20y = -4x

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4 years ago

Plz help me Find LM.

Ira Lisetskai [31]

Because LP and NP are the same measure, that means that MP is a bisector. It bisects side LN and it also bisects angle LMN. Where MP meets LN creates right angles. What we have then thus far is that angle LMP is congruent to angle NMP and that angle LPM is congruent to angle NPM and of course MP is congruent to itself by the reflexive property. Therefore, triangle LPM is congruent to triangle NMP and side LM is congruent to side NM by CPCTC. Side LM measures 11.

3 0

3 years ago

is (-1/2 x + 6/7) - (7/2 x - 4/7) equivalent to -4 x + 2/7 ? use the properties of operations to justify your answer

LuckyWell [14K]

Answer:

The given equation is NOT justified.

Step-by-step explanation:

Here, the given equation is $(\frac{-1}{2}x + \frac{6}{7} ) - (\frac{7}{2}x - \frac{4}{7} )$ = $-4x + \frac{2}{7}$

Now, here Consider the left hand side and simplifying the left side by operating on the like terms,

⇒ $(\frac{-1}{2}x + \frac{6}{7} ) - (\frac{7}{2}x - \frac{4}{7} )$ = $\frac{-1}{2}x + \frac{6}{7} - \frac{7}{2}x + \frac{4}{7} = (\frac{-1}{2}x -\frac{7}{2}x) + (\frac{6}{7} + \frac{4}{7})$

= $(\frac{-1 - 7}{2}x ) + (\frac{6 + 4}{7} ) = \frac{-8x}{2} + \frac{10}{7} \neq -4x + \frac{2}{7}$

Here, Left side of equation ≠ Right side of the equation

Hence, $(\frac{-1}{2}x + \frac{6}{7} ) - (\frac{7}{2}x - \frac{4}{7} )$ ≠ $-4x + \frac{2}{7}$

4 0

3 years ago