When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)
Thus there are 11 total possible outcomes.
Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)
This means there are 7 outcomes with sum greater than or equal to 9.
Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11
So, option A gives the correct answer
Just add up all the sides
X + y = 5
xy = 12
x + y = 5
y = -x + 5
xy = 12
x(-x + 5) = 12
x(-x) + x(5) = 12
-x² + 5x = 12
- 12 - 12
-x² + 5x - 12 = 0
x² - 5x + 12 = 0
x = 5 ± √25 - 48
2
x = -5 ± √-23
2
x = -5 ± 4.79i
2
x = -5 + 4.79i or x = -5 - 4.79i
2 2
x = -2.5 + 2.395i or x = -2.5 - 2.395i
y = -2.5 - 2.395i or y = -2.5 + 2.395i
The two numbers that add up to 5 and multiply to 12 is -2.5 ± 2.395i, which is -2.5 + 2.395i and -2.5 - 2.395i.
Answer:
y= -6
x=14
Step-by-step explanation:
in attachment
Answer:
DIE DIE DIE
OVERWATCH
Step-by-step explanation:
