Answer:
Multiply the first equation by 4.
Step-by-step explanation:
4(x+y=3) which gives
4x+4y=12
and
4x-y=7
Then subtract the two equations and the x variable will be eliminated.
The answer is square root 6/2
You're looking for the largest number <em>x</em> such that
<em>x</em> ≡ 1 (mod 451)
<em>x</em> ≡ 4 (mod 328)
<em>x</em> ≡ 1 (mod 673)
Recall that
<em>x</em> ≡ <em>a</em> (mod <em>m</em>)
<em>x</em> ≡ <em>b</em> (mod <em>n</em>)
is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly
1 ≡ 4 (mod 41)
is not true.
So there is no such number.
Answer:
0.016
Step-by-step explanation:
u divide 0.048 by 30 and the result is the answer
Answer:
It will take 34.33
Step-by-step explanation:
* Lets talk about the compound continuous growing
- Compound continuous growing can be calculated using the formula:

# A = the future value
# P = the initial amount
# r = the growing rate in decimal
# t = the time
* Lets solve the problem
- The population of a particular country is growing at 3.2 %
compounded continuously
∴ r = 3.2/100 = 0.032
- We need to find how long will it take the population to triple
∵ The initial population is P
∴ A = 3P
∵ 
∴ 
- Divide both sides by P
∴ 
- Insert ㏑ for both sides
∴ 
- Remember 
∴ ㏑(3) = 0.032t
- Divide both sides by 0.032
∴ t = ㏑(3)/0.032 = 34.33
* It will take 34.33