1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
agasfer [191]
3 years ago
10

The explicit formula for the geometric sequence Negative one-ninth, one-third, negative 1, 3, negative 9, ellipsis is f (x) = ne

gative one-ninth (negative 3) Superscript x minus 1. What is the common ratio and recursive formula for this sequence?
Mathematics
1 answer:
storchak [24]3 years ago
3 0

Answer:

Common ratio, r=-3

Recursive Formula

f(n)=-3f(n-1),$   $n\geq 2\\f(1)=-\dfrac{1}{9},

Step-by-step explanation:

The formula for the geometric sequence: -\dfrac{1}{9} ,\dfrac{1}{3}, -1,3,-9,\cdots is given as:

f(x)=-\dfrac{1}{9}(-3)^{x-1}

<u>Common Ratio</u>

Dividing the next terms by the previous terms, we obtain:

\dfrac{1}{3} \div -\dfrac{1}{9} = \dfrac{1}{3} \times -9 =-3\\3 \div -1 =-3\\-9 \div 3 =-3

Therefore, the common ratio of the sequence, r=-3

<u>Recursive Formula</u>

We observe that the next term, f(n) is obtained by the multiplication of the previous term. f(n-1) by -3.

Therefore, a recursive formula for the sequence is:

f(n)=-3f(n-1),$   $n\geq 2\\f(1)=-\dfrac{1}{9},

You might be interested in
448 = -5v + 8(-5 - 7v)<br> What is v?
lapo4ka [179]

Answer:

v = -8

Step-by-step explanation:

First we would have to distribute the 8(-5 - 7v). To do this we would multiply 8 by -5 and 8 by -7v to get 448=-5v-40-56v. After this, we would have to simplify like terms by subtracting 56v from -5v to get 448=-61v-40. We now have to get the variable on one side and to do that, we can add 40 to both sides to get 488=-61v. Finally to get the variable alone, we would have to divide both sides by -61 to get v=-8.

Brainliest would be appreciated!

3 0
2 years ago
Read 2 more answers
What is the value of 6n - 2 when n = 3?
Yuliya22 [10]

Answer:

16

Step-by-step explanation:

Substitute 3 for n,

6(3) - 2

then multiply

18 - 2

then subtract

16

8 0
3 years ago
When two fractions are between 0 and 1/2, how do you know which fraction is greater? explain
loris [4]
Two fraction between 0 and 1/2 and 1/3 and 1/6. 1/3 = .33 and 1/6= .16. we know that 1/3 is greater than 1/6 because the value is larger. .33 > .16

.33 is definitely greater than 1.6
4 0
3 years ago
FIRST ONE TO ANSWER GETS A BRAINLY!!!! PLZ ANSWER AND HELP ME!!! PLS ALSO TELL HOW YOU GOT THE ANSWER!!!
KengaRu [80]

Answer:

Square root of 87.35 will be plotted between 9 and 10 as shown below.

Step-by-step explanation:

We are given that, 'The number line is numbered in tenths'

Also, the square root of 87.35 is given by,

\sqrt{87.35}=9.4

That is, we have to plot the point 9.4 on the number line numbered in tenths.

As, 9.4 will lie between the points 9 and 10.

Thus, we get that square root of 87.35 will be plotted between 9 and 10 as shown below.

8 0
3 years ago
The temperature in the Arctic Circle at 9:00am was 22.8° below zero. By 6:00pm on the same day, the temperature had decreased by
rosijanka [135]
4.65 is the new temperature.
8 0
3 years ago
Other questions:
  • 3(x+4)=5(x-2) I really need help i have no idea how to do it
    15·2 answers
  • For every sale of $50, a company pays its salesperson an incentive of $5.
    11·1 answer
  • If you have 30 questions how much time do you have to take the test
    5·1 answer
  • I need help on this!!
    7·2 answers
  • Um help me please !!!
    10·1 answer
  • WWhat is the difference of the polynomials?
    14·1 answer
  • 10. Which points are on the line that passes through (-4,-3), (20, 15), and (48, 36) ?<br>​
    7·1 answer
  • What is the range?<br><br> (-7, 4) (2, 6) (1, -3) (5, 0) (9, -1)
    11·1 answer
  • Which table represents a linear function
    6·2 answers
  • Write 9n + 1 in a word phrase <br><br> 9n +1
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!