PVI, so the power used would be 240*5= 1200 Watts.
Answer:
534 ft
Explanation:
given,
speed of the vehicle = 60 mph
1 mph = 0.447 m/s
60 mph = 60 x 0.447 = 26.82 m/s
stopping distance = ?
Stopping distance of the car is equal to the distance traveled in the reaction time and the braking distance.
Reaction time of a common person = 1.5 s
taking coefficient of friction of the road = 0.3
using equation of stopping sight distance
S.D = RD + BD
RD is Reaction distance
RD = v t_r
RD = 26.82 x 1.5
RD = 40.23 m
BD is the braking distance


BD = 122.33 m
Stopping sight distance
SD = 40.23 + 122.33
SD = 162.56 m
1 m = 3.28 ft
162.56 m = 162.56 x 3.28
= 533.20 ft ≈ 534 ft
hence, the stopping distance will be equal to 534 ft
Answer:
Explanation:
Falling objects form an interesting class of motion problems. For example, we can estimate the depth of a vertical mine shaft by dropping a rock into it and listening for the rock to hit the bottom. By applying the kinematics developed so far to falling objects, we can examine some interesting situations and learn much about gravity in the process.