Answer:
314 ft²
Step-by-step explanation:
Data provided in the question:
Depth (height) of the pool = 
of its radius
let the radius be 'r' ft
thus,
Depth (height) of the pool, h = 
ft
Volume of the pool = 1570 ft³
also,
Volume of cylinder = πr²h
thus,
1570 ft³ = πr²h
or
1570 ft³ = 
or
3140 = 3.14 × r³ [ π = 3.14 ]
or
r³ = 1000 ft³
or
r = 10 ft
Thus,
Area of the bottom surface = πr²
= 3.14 × 10²
= 314 ft²
Answer:
Between 15.95 ounces and 16.15 ounces.
Step-by-step explanation:
We have the following value m, being the mean, sd, being the standard deviation and n, the sample size:
m = 16.05
sd = 0.1005
n = 4
We apply the formula of this case, which would be:
m + - 2 * sd / (n ^ 1/2)
In this way we create a range, replacing we have:
16.05 + 2 * 0.1005 / (4 ^ 1/2) = 16.1505
16.05 - 2 * 0.1005 / (4 ^ 1/2) = 15.9495
Which means that 95% of all samples are between 15.95 ounces and 16.15 ounces.
1,5,25
I write all the multiples that equal 25 out,
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