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3 years ago

Which description of the graph of y=110x is most accurate?

Mathematics

1 answer:

hodyreva [135]3 years ago

6 0

Answer:

The correct option is;

The graph is a line that rises steeply from left to right and passes through the origin

Step-by-step explanation:

The given equation is y = 110·x

Comparing the given equation to the general equation of a straight line, y = m·x + c

Where;

m = The slope of the straight line graph

c = The y-intercept

We have;

The slope of the given equation, y = 110·x = 110

The y-intercept, which is given by the constant c in the given equation = (0, 0)

Therefore, by the slope of the equation, for each unit increase in x, y increases by 110, therefore, the graph is a straight line that rises steeply and passes through the origin

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On a hiking trip, Melissa notes that she hikes about 16 kilometers every 2.5 hours. If she continues at this rate, about how man

svp [43]

Answer:

so if she hike 12 km every 4 hours, how many km could she hike in 6 hours.

first u have to find the equation. 12 km=4hours

? =6hours

and then you have to multiply 12 km by 6 hours and divide the results by 4 which is 12×6÷4. the final answer will be 18 kilometers.

Step-by-step explanation:

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3 years ago

The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers

stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0

4 years ago