if the temperature at kiev city is 0 Celsius it rises by 6 Celsius over the next 6 hrs what is the temperature at 6pm
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Given the radius of 50 miles and the line joining the cities at (0, 56) and (58, 0), the transmitter signal can be picked during 59.24 miles of the drive.
<h3>How can the duration of signal reception be found?</h3>Radius of broadcast of the transmitter = 50 miles
Location of starting point = 56 miles north of the transmitter
Location of destination city = 58 miles east of the transmitter
Therefore we have;
Slope of the line joining the two cities
= 56 ÷ (-58) = -0.966
Which gives the equation of the line as follows;
y = -0.966•x + 56
The equation of the circle is;
1.933156•x^2 - 108.192•x + 636 = 0
Which gives;
- x = 6.67 or x = 49.29
Therefore;
When x = 6.67, we have;
- y = -0.966 × 6.67 + 56 = 49.56
When x = 49.29, we have;
- y = -0.966 × 49.29 + 56 = 8.4
The length of the drive, during which the driver can pick the signal, <em>l</em>, is therefore;
l = √((49.56-8.4)^2 + (49.29-6.67)^2) = <u>59.24 miles</u>
- The length of the drive during which the signal is received is 59.24 miles
Learn more about the equation of a circle here:
#SPJ1
Answer: The following statements are true:
It is symmetrical.
The first diagonal is all 1’s.
The second diagonal is the counting numbers.
Any number in the triangle is the sum of the two numbers directly above it.
Each row adds to a power of 2.
