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Viefleur [7K]
2 years ago
15

Could you please awnser all 3 questions ​

Mathematics
1 answer:
12345 [234]2 years ago
4 0

Answer:

1) f(5) = 7

2) f(0) = -2

3) p(-7) = -17

Step-by-step explanation:

1) f(a) = 2a - 3

f(5) = 2 · 5 - 3 = 10 - 3 = 7

2) f(x) = 2x - 2

f(0) = 2 · 0 - 2 = 0 - 2 = -2

3) p(n) = 2n - 3

p(-7) = 2 · (-7) - 3 = -14 - 3 = -17

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An equilateral triangle ΔLMQ (see picture to the right) is drawn in the interior of square LMNP so that side is common. Find m∠L
lesya692 [45]
I don’t see the picture if I see it I can help you tho
5 0
2 years ago
Solve the following equation for x: 6(4x+5)= 3(x+8)+3. Round to the nearest hundredth.
gavmur [86]
6(4x + 5) = 3(x + 8) + 3
24x + 30 = 3x + 24 + 3
24x + 30 = 3x + 27
24x - 3x = 27 - 30
21x = - 3
x = -3/21
x = - 0.143 <==
8 0
2 years ago
Read 2 more answers
One parent is a cystic fibrosis carrier, and the other has
Marysya12 [62]

Answer:

A - 0%

B- 50%

C- 50%

D- 100%

Step-by-step explanation:

Cystic fibrosis is inherited in an autosomal recessive form, meaning that a person has to inherit two abnormal genes for the disease to manifest. In the case of this question, one parent is a gene carrier, so his genotype is Aa, while the other does not have the cystic fibrosis gene, so AA.

Performing the cross of Aa x AA, we can see that:

a.) The probability of a child would have cystic fibrosis is 0%, since the disease is recessive and to be affected it should receive a recessive gene from each parent.

b.) The probability of a child would be a carrier is 50%, as 50% of the crossing phenotypes are Aa.

c.) The probability of a child would not have cystic fibrosis and is not a carrier is 50%, as 50% of the child's genotype is AA.

d.) The probability of a child would be healthy is 100%, as of all possible phenotypes none is affected.

5 0
3 years ago
If a person can walk with an average speed of 5 meters/second, how far will they walk in 8 minutes?
sineoko [7]

Answer:

2,400

Step-by-step explanation: If a person can walk 5 meters per second and there are 60 seconds in a minute then you would multiply 5 by 60 and get 300. Then you multiply that by 8 and get 2,400.

5 0
3 years ago
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A jar contains 2 orange, 4 green, 2 white and 2 black balls. What is the probability of drawing an orange ball without putting i
KonstantinChe [14]

Answer:

2/45

Step-by-step explanation:

We are told that:

A jar contains 2 orange, 4 green, 2 white and 2 black balls.

The total number of balls in the jar is calculated as:

2 orange balls + 4 green balls + 2 white balls + 2 black balls = 10 balls

The probability of drawing an orange ball = P(Orange) = 2/10

The probability of drawing a black ball = P(Black) = 2/10

Therefore, the probability of drawing an orange ball without putting it back, then drawing a black ball is calculated as:

2/10 × 2/9 = 4/90

= 2/45

7 0
3 years ago
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