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Vsevolod [243]
3 years ago
8

Boston terrier weigh up to 25 pounds . suppose a puppy of this breed weighs 15 pounds.write equality and solve for how much more

this dog could weigh
Mathematics
2 answers:
labwork [276]3 years ago
4 0

Answer: This dog could weigh 10 pounds more.

Step-by-step explanation:

Hi, the total weight that a Boston terrier cam reach is 25 pounds, so, that weight must be equal to the actual weight of a puppy of that breed (15) plus the remaining pounds to reach full weight (w)

Mathematically speaking:

15 + w = 25

Solving for w:

w =25-15

w = 10  pounds

This dog could weigh 10 pounds more.

Feel free to ask for more if needed or if you did not understand something.

Molodets [167]3 years ago
3 0

Answer:

25-15=w;w=10

Step-by-step explanation:

25 is the most it can weigh, and 15 is how much it weighs at the moment. The w stands for how much the weight can go up.

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Find the value of x in each case. Give reasons to justify your solutions!
tangare [24]

Answer:

x=27°

Step-by-step explanation:

we know that

<u><em>The Triangle Exterior Angle Theorem</em></u>, states that: An exterior angle of a triangle is equal to the sum of the opposite interior angles

step 1

Find the measure of angle PLM

we know that

m∠PLM+m∠LPM=m∠PMN ----> by Triangle Exterior Angle Theorem

we have

m∠LPM=x°

m∠PMN=2x+72°

substitute

m∠PLM+x=2x+72°

m∠PLM=2x-x+72°

m∠PLM=x+72°

step 2

Find the measure of angle x

we know that

3x+m∠PLM=180° ----> by supplementary angles (form a linear pair)

we have

m∠PLM=x+72°  (see step 1)

substitute

3x+x+72°=180°

4x=180°-72°

4x=108°

x=27°

4 0
3 years ago
Read 2 more answers
Find the measure of x. Line PU has points R and S between points P and U, lines QR and ST are parallel, line QR intersects line
Genrish500 [490]

The value of x is 1.

* Let's explain how to solve the problem

- Line PU has points R and S between points P and U

- Line QR intersects line PU at point R

- Line ST intersects line PU at point S

- Lines QR and ST are parallel

- Look to the attached figure

∵ QR // ST

∴ m∠TSU = m∠QRU ⇒ corresponding angles

∵ m∠TSU = 15(x + 2)°

∴ m∠QRU = 15(x + 2)

∵ Points P, R, S lie on the same line

∵ RQ intersects PS at R

∵ m∠PRQ + m∠QRU = 180° ⇒ straight angle

∵ m∠PRQ = 135°

∵ m∠QRU = 15(x + 2)°

∴ 135 + 15(x + 2) = 180

∴ 135 + 15x + 30 = 180

- Add like terms

∴ 15x + 165 = 180

- Subtract 165 from both sides

∴ 15x = 15

- Divide both sides by 15

∴ x = 1

∴ The value of x is 1

In geometry, parallel lines are coplanar instantly traces that do not intersect at any factor. Parallel planes are planes in identical three-dimensional space that in no way meet. Parallel curves are curves that do not touch every different or intersect and hold a set minimal distance

In mathematics, the intersection of or more gadgets is any other item that includes the whole thing that is contained in all the items simultaneously.

Learn more about parallel lines here : brainly.com/question/24756209

#SPJ4

4 0
2 years ago
Need help answering this
AVprozaik [17]
This is cross multiplication.
513.74 times x =513.74x
16.26 times 100=1626
Now there is 1626=513.74x
Do 1626 divided by 513.74 which is 3.16502511
4 0
3 years ago
Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence
Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

\lim_{x \to c} \frac{x^2-cx}{(x-c)}

We can simplify it

\lim_{x \to c} \frac{x(x-c)}{(x-c)}

=\lim_{x \to c} x

=c

so, we can see that limit exist and it's value defined

case-2:

\lim_{x \to c} \frac{1}{(x-c)}

Left limit is

\lim_{x \to c-} \frac{1}{(x-c)}

=-\infty

Right Limit is

\lim_{x \to c+} \frac{1}{(x-c)}

=+\infty

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0
3 years ago
HELP PLEASE NEEDED !!
Molodets [167]

Answer:

\sqrt[3]{125^2} \\= 125^2/3

125^2/3=25

So Jen is correct

4 0
3 years ago
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