Answer:
hole at x=-3
Step-by-step explanation:
The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)
The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.
So anyways we have (x+3)/(x^2-9)
= (x+3)/((x-3)(x+3))
Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.
There is no other equations
The last option is the correct option.
You basically just have to solve for e.
so multiply each side by 4 first.
that makes it 3e < 96
to get e by itself divide each side by 3.
which you e < 32
2+3=6
3+2=6
6-3=2
6-2=3
6/2=3
6/3=2
Is that what you are looking for?
