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3241004551 [841]
3 years ago
6

Simplify -3c+5d+3c-d

Mathematics
2 answers:
Rina8888 [55]3 years ago
8 0

Answer:

4d

-3x+3c+5d-d

=0+4d

=4d

EastWind [94]3 years ago
4 0

Answer:

4d

Step-by-step explanation:

-3c+5d+3c-d

=-3c+3c+5d-d

=4d

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The play director spent 190190190190 hours preparing for a play. That time included attending 35353535 rehearsals that took vary
Genrish500 [490]

Answer:

The equation above represents the total time the play director spent preparing for a play.

Step-by-step explanation:

The time spent by the play director for preparing for a play is, 190 hours.

Of these 190 hours, the director spent varying amounts of time attending 35 rehearsals for the play.

Let the varying amounts of time be denoted by, <em>x</em>.

The director also spent 3/4th of an hour, i.e. 45 minutes, on other responsibilities related to the play.

The equation provided is:

35x+\frac{3}{4}=190

The equation above represents the total time the play director spent preparing for a play.

7 0
3 years ago
32 + a &gt; 44; 11, 12, 13
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4 0
3 years ago
A lighthouse is built on an exposed reef, 4.5 miles off-shore. The shoreline is perfectly straight, and a town is located 6 mile
Alisiya [41]

Answer: 3.94 hours

Step-by-step explanation:

From the question, the following parameters are given:

Distance offshore = 4.5 miles

Distance downshore = 6 miles

Speed when running = 3.4 mph

Speed with boat = 1.8 mph

distance of boat rowing = sqrt(4.5^2 + x^2)

Where

Speed = distance/time

Time = distance/speed

Time = distance of boat rowing/1.8

distance of running = 6 - x

Time = (6-x)/3.4

total travel time

t = sqrt(4.5^2 + x^2)/1.8 + (6 - x)/3.4

dt/dx = x/(1.8×sqrt(4.5^2 + x^2) - 1/3.4

d^2t/dx^2 = +ve at any x

x is at its minimum when dt/dx=0

x/(1.8×sqrt(4.5^2 + x^2) = 1/3.4

x = 6/sqrt(253) × 4.5 = 1.697 miles

Substitute x in

t = sqrt(4.5^2 + x^2)/1.8 + (6 - x)/3.4

We obtaine

t = sqrt(4.5^2 + 1.697^2)/1.8 + (6 - 1.69)/3.4

t = 2.672+ 1.266 = 3.94 hours

7 0
3 years ago
Each side of a sandbox is 7 feet long. It will cost $1.00 per square foot to replace the sand in the sandbox. What would be the
arlik [135]

Answer: $7.00

Step-by-step explanation:

each foot is $1, so times 7 is 7 dollars.

3 0
3 years ago
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Simply 7/4 squared ​
klemol [59]

Answer:

0.4375

Step-by-step explanation:

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3 years ago
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