The length of the rectangle is 3 cm and the width is 5 cm what will the area be?

Abigail starts work at 8:00 am and Zavier starts at 7:00 am. They both finish at the same time. If abigail works x hours, how ma

Tamiku [17]

X+1 Hours, because Zavier begins work an hour earlier than Abigail.

7 0

2 years ago

Read 2 more answers

Solve 4 + 4 ( x - 2 ) = 2 ( x + 1 ) - x The question requires you to show your work

kati45 [8]

Answer:

x = 2

Step-by-step explanation:

Step 1 :

Equation at the end of step 1 :

(4+(4•(x-2)))-(2•(x+1)-x) = 0

Step 2 :

Equation at the end of step 2 :

(4 + 4 • (x - 2)) - (x + 2) = 0

Step 3 :

Step 4 :

Pulling out like terms :

4.1 Pull out like factors :

3x - 6 = 3 • (x - 2)

Equation at the end of step 4 :

3 • (x - 2) = 0

Step 5 :

Equations which are never true :

5.1 Solve : 3 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

5.2 Solve : x-2 = 0

Add 2 to both sides of the equation :

x = 2

One solution was found :

x = 2

Processing ends successfully

plz mark me as brainliest :)

7 0

4 years ago

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$

So, root of the equation =0.205 (Approx)

Approximate relative error

$=\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41$

Approximate relative error in terms of Percentage

=0.41 × 100

= 41 %

7 0

3 years ago

Point R is on line segment QS. Given QS= 5x-2, QR= 3x-6, and RS=4x-2, determine the numerical length of RS.

pashok25 [27]

Answer:

The numerical length of RS is 10 units

Step-by-step explanation:

* Lets explain How to solve the problem

- Point R is on line segment QS

- The length of QS is (5x - 2)

- The length of QR is (3x - 6)

- The length of RS is (4x - 2)

- The length of QS is the sum of the lengths of QR and RS

∵ QS = QR + RS

∴ (5x - 2) = (3x - 6) + (4x - 2)

- Simplify the right hand side by adding like terms

∴ 5x - 2 = (3x + 4x) + (-6 + -2)

∴ 5x - 2 = 7x + -8 ⇒ (+)(-) = (-)

∴ 5x - 2 = 7x - 8

- Add 8 for both sides

∴ 5x + 6 = 7x

- Subtract 5x from both sides

∴ 6 = 2x

- Divide both sides by 2

∴ x = 3

- To find the length of RS substitute the value of x in its expression

∵ RS = 4x - 2

∵ x = 3

∴ RS = 4(3) - 2 = 12 - 2 = 10

∴ The numerical length of RS is 10 units

8 0

3 years ago

Whats equivalent to 3.5 x 100.

ioda

Answer:

350

Step-by-step explanation:

since there are 2 zeros in "100", move the decimal over 2 places

4 0

3 years ago