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Tema [17]
3 years ago
7

Frank earns $7.96 per hour at his job. He worked 38.5 hours last week. How much money did he earn last week?

Mathematics
2 answers:
ahrayia [7]3 years ago
4 0

Answer:

306 dollars 46 cents

Step-by-step explanation:

I asked siri.

almond37 [142]3 years ago
3 0

Answer: $306.46

Step-by-step explanation:

7.96 x 38.5

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emmasim [6.3K]

Answer:

4

Step-by-step explanation:

<h3><u>some relevant limit laws</u></h3>

lim C = C where c is a constant.

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lim( f(x)g(x)) =lim f(x) * lim g(x)

lim( cg(x)) =clim g(x)

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\lim_{n \to 3} g(x)  = 9\\\\\lim_{n \to 3} f(x)  = 6\\\\ \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10} \\\\ = \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10}\\\\= \sqrt[3]{lim_{n \to 3}f(x) \times lim_{n \to 3}g(x) + 10}\\\\= \sqrt[3]{6 \times 9 + 10}\\\\= \sqrt[3]{64}

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4 0
3 years ago
Write as a single number. log464 + log536
scoundrel [369]

Answer:

1000

Step-by-step explanation:

6 0
3 years ago
Please help!! cause this is really confusing
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3 years ago
determine the base, b, of the exponential model. Is the base a growth or decay factor? a. b is 0.6394; It is a growth factor. b.
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An exponential model can be described by the function
f(x) = a(b)^x
where: a is the initial population or the starting number, b is the base and x is the number of periods elapsed.

When the base of an exponential model is greater than 1 it is called a growth factor, but when it is less than 1 it is called a decay factor.

Given the exponential model
n=20.5(0.6394)^t
n is the final output of the exponential model, 20.5 is the starting number, 0.6394 is the base and t is the number of periods/time elapsed.

Here, the base is 0.6394 which is less than 1, hence a decay factor.

Therefore, <span>the base, b, of the exponential model is 0.6394; It is a decay factor.</span>
8 0
3 years ago
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