All categories

3 years ago

Help me please, This is due in a little

Mathematics

2 answers:

erik [133]3 years ago

6 0

Answer:

Linear.

Why?

Y= 10 x 2^x

Is a linear because when a number has "^x" in it that means it is a linear.

Aleks04 [339]3 years ago

6 0

Linear because y=0 was just asking ty

You might be interested in

If the measure of is 232°, what is the measure of ∡DEF?.

riadik2000 [5.3K]

To answer this specific problem, the measure of ∡DEF is 64. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

3 0

3 years ago

Evaluate: 5-3 xwhen x=-7 Substitute-7 for x.

Mice21 [21]

The answer for this question is 26

7 0

3 years ago

On the first play of the game, the Wildcats gained 8 yd. What integer represents a gain of 8 yd?

vesna_86 [32]

The integer 8 represents a gain of 8 yards.

4 0

3 years ago

Read 2 more answers

If I have a triangular prism with the length of 9mm, the base of 6.6 mm, and the height 4 mm or 5.2 mm. What would be the surfac

Lelu [443]

The surface area of triangular prism is 117.12 mm²

<u>Explanation:</u>

Base side, a = 9 mm

Base side, b = 6.6 mm

Base side, c = 5.2 mm

Height, h = 4 mm

Total surface area = ?

We know,

Surface area, A = 2 Ab ( a+b+c) h

Ab = √s(s-a) (s-b) (s-c)

s = a+b+c/2

Solving for A

A = ah + b h + ch + 1/2 √ -a⁴ + 2(ab)² + 2(ac)² - b⁴ + 2 (b c)² - c⁴

A = 9.4 + 6.6 X 4 + 5.2 X 4 + 1//2 √ -9⁴ + 2(9 X 6.6)² + 2(9 X 5.2)² - (6.6)⁴ + 2 (6.6 X 5.2)² - (5.2)⁴

A = 117.12 mm²

Therefore, the surface area of triangular prism is 117.12 mm²

4 0

3 years ago

Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$

$Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------$

$Answer:\\\large\boxed{-1+i}\\----------------------$

$Hope~This~Helped!~Good~Luck!$

8 0

4 years ago

Read 2 more answers