Answer:
The required equation is: 
Step-by-step explanation:
We need to find equation from the table given
x f(x)
3 -5
7 -2
11 1
15 4
We can write equation in the form of 
where m is slope and b is y-intercept.
Finding Slope
We can used the slope formula to find slope: 
From the table we have: 
Putting values and finding slope
So, we get slope 
Now, finding y-intercept
Using the slope and point (3,-5) we can find y-intercept
The y-intercept is 
So, the equation having slope and y-intercept will be:
The required equation is:
<span>We use ratio and proportion to solve each of these:
</span><span>
</span><span>1.
The scale of a map is 1 in = 19.5 mi map: ________ in actual: 9.5 mi
</span><span>1 in / 19.5 mi = x in / 9.5 mi, x = 0.487 in
</span><span>
</span><span>2.
The scale of a map is 7 in = 16 mi map: 4.9 in actual: ______ mi
</span><span>7 in / 16 mi = 4.9 in / x mi, x = 11.2 mi
</span><span>
</span><span>3. The
scale factor for a model is 5 cm = ________ m Model : 72.5 cm actual:
165.3 m
</span><span>5 cm / x m = 72.5 cm / 165.3 m, x = 11.4 m
</span><span>
</span><span>4. The scale of a map is 1 in = 9.6 mi map: ________ in actual:
34.7 mi
</span><span>1 in / 9.6 mi = x in / 34.7 mi, x = 3.62 in
</span><span>
</span><span>5. The scale of a map is 1 ft = 9.6 mi map: ________ ft actual:
38.4 mi
</span><span>1 ft / 9.6 mi = x ft / 38.4 mi, x = 4 ft
</span><span>
</span><span>6. The scale factor for a model is 5 cm = ________ m Model :
22.4 cm actual: 155.2 m
</span><span>5 cm / x m = 22.4 cm / 155.2 m, x = 34.64 m
</span><span>
</span><span>7. The scale of a map is 5 in = 10 mi map: 8.7
in actual: ______ mi
</span><span>5 in / 10 mi = 8.7 in / x mi, x = 17.4 mi
</span><span>
</span><span>8. The scale of a map is 1 in = 13.5 mi map:
________ in actual: 65.9 mi
</span><span>1 in / 13.5 mi = x in / 65.9 mi, x = 4.88 in
</span><span>
</span><span>9. The scale factor for a model is 5 cm =
________ m Model : 61.5 cm actual: 143.2 m
</span><span>5 cm / x m = 61.5 / 143.2 m, x = 11.64 m
</span><span>
</span><span>10. The scale factor for a
model is 5 cm = ________ m Model : 29.7 cm actual: 179.5 m
</span><span>5 cm / x m = 29.7 cm / 179.5 m, x = 30.22 m
</span>
The answer is , c. 3.4 lol
Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: number of daily text messages a high school girl sends.
This variable has a population standard deviation of 20 text messages.
A sample of 50 high school girls is taken.
The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:
X[bar]≈N(μ;δ²/n)
This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:
Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)
a.
P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836
b.
P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)
P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328
I hope you have a SUPER day!
