B, (0,3)
If you plot each point this is the only one that touches the line.
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Explanation:
Here's one way to go at it.
Draw segments AB and CO. Define angles as follows. (The triangles with sides that are radii are all isosceles, so their base angles are congruent.)
x = angle OAB = angle OBA
y = angle OAC = angle OCA
z = angle OBC = angle OCB
Consider the angles at each of the points A, B, C.
At A, we have ...
angle CAB = x + y
At B, we have ...
angle CBA = x + z
At C, we have ...
angle ACB = y + z
The sum of the angles of triangle ABC is 180°, as is the sum of angles in triangle ABO. This gives ...
x + x + ∠AOB = (x+y) +(x+z) +(y+z)
∠AOB = 2(y+z) = 2∠ACB
This shows ∠AOB = 2×∠C, as required.
Answer:
Option 3
Step-by-step explanation:
Answer:
Step-by-step explanation:
We are given the two functions:
And we want to find:
This is equivalent to:
So, evaluating f(-1) first, we acquire:
Then by substitution:
So:
Therefore:
Your answer is indeed correct.
