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Keith_Richards [23]
3 years ago
9

13) A rectangular garden has an area of 45 square meters. The garden will be 4 meters longer than its width Write and sowe an eq

uation to find the dimensions in meters.​
Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

9m ×5m

Step-by-step explanation:

Area of a rectangle= length ×width

Let the width be W meters and the length be L meters.

2 equations can be written from the given information:

45= WL -----(1)

L= W +4 -----(2)

Substitute (2) into (1):

45= W(W +4)

<em>Expand:</em>

45= W² +4W

<em>-45 on both sides:</em>

W² +4W -45= 0

<em>Factorise:</em>

(W +9)(W -5)= 0

W+9=0 or W-5=0

W= -9 or W= 5

(reject)

Substitute W= 5 into (2):

L= 5 +4

L= 9

∴ The dimensions of the garden is 9m ×5m.

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iren2701 [21]

Answer:

it is a simultaneous equation and I used Elimination method

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Zigmanuir [339]

ANSWER:

a. (1, 0)

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f.

\begin{equation*} \text{Domain: }\left(-\infty\:,\:-2\right)\cup\left(-2,\:3\right)\cup\left(3,\:\infty\:\right) \end{equation*}

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We have the following function:

f\left(x\right)=\frac{x-1}{x^2-x-6}

The graph corresponding to the function is the following:

We determine in each case what the statement asks for, like this:

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\begin{gathered} \text{ in this case y = 0, therefore:} \\  \\ \frac{x-1}{x^2-x-6}=0 \\  \\ x-1=0\cdot(x^2-x-6) \\  \\ x=1 \\  \\ \text{The x-intercept is \lparen1, 0\rparen} \end{gathered}

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c. the equation(s) of any vertical asymptote(s). The horizontal asymptotes are the values that x cannot take since the function would be discontinuous for those values.

In this case, since it is a rational function, it would be when the denominator is 0, therefore, we solve the following:

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