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3 years ago

Help me please I need it!!!

Biology

2 answers:

sweet-ann [11.9K]3 years ago

3 0

Answer:

Explanation:

I would say that your answer would be A.) seeds. Plants don't even have reproductive organs, so that answer would be a definite no. Pollen and nectar comes from both trees and flowers, not fruit. So, that would make your answer seeds.

s2008m [1.1K]3 years ago

3 0

The answer to your question is A

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What is the ratio of surface area to volume for a sphere with the following

Leya [2.2K]

Answer:

$0.4\ \frac{1}{m}$

Explanation:

Let

x ----> the surface area of a sphere

y ---> the volume of a sphere

we know that

The ratio of surface area to volume of a sphere is equal to divide the surface area by the volume of the sphere

$\frac{x}{y}$

we have

$x=588\ m^2\\y=1,372\ m^3$

substitute the values

$\frac{588}{1,372}=0.4\ \frac{1}{m}$

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3 years ago

Both liver cells and lens cells have the genes for making the proteins albumin and crystalline. However, only liver cells expres

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The correct statement is liver cells possess transcriptional activators that are different from those of lens cells.

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Transcriptional activators are factors that enable the expression of certain genes in particular cell types.

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2 years ago

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3 years ago

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Describe how rodent and human skeleton's are similar in structure and function. HELP!

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2 years ago

A population of 100 tigers has 30 with horizontal stripes. Using pedigrees, you ascertain that horizontal striping is caused by

bixtya [17]

Assuming that this population is in Hardy-Weinberg equilibrium, we can sayt that the probability that, given enough time, all tigers in the population will have horizontal stripes is 30% = 0.3.

--------------------------

Available data:

Population size, N = 100 tigers
Number of Tigers with horizontal stripes = 30
Horizontal stripes is caused by an autosomal recessive mutation.

We need to know the probability that all tigers in the population will have horizontal stripes, which is the recessive phenotype.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of horizontal striped individuals in the population.

There are 100 individuals, and only 30 have horizontal stripes.

So, the phenotypic frequency, F(HS) is 30/100 = 0.3 = 30%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(hh) = 30%

Finally, we can get the allelic frequency by taking the square root of this value.

F(hh) = q² = 0.3

f(h) = q = √0.3 = 0.55 = 55%

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