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Juliette [100K]
3 years ago
5

What is the value of 3-(2/3) cubed 2

Mathematics
1 answer:
Scilla [17]3 years ago
8 0

Answer:

2.77777778

2/3 cubed is 0.222222222 and 3-2/3^2 is 2.77777778

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What is the coefficient of x2y3 in the expansion of (2x + y)5?
Zigmanuir [339]

Option C:

The coefficient of x^{2} y^{3} is 40.

Solution:

Given expression:

(2 x+y)^{5}

Using binomial theorem:

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here a=2 x, b=y

Substitute in the binomial formula, we get

(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}

                                                            $+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}

Let us solve the term one by one.

$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}

$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y

$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}

$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}

$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}

$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}

Substitute these into the above expansion.

(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}

The coefficient of x^{2} y^{3} is 40.

Option C is the correct answer.

5 0
2 years ago
Examine the word PROBABILITY, if a letter is picked at random, find probability that 13 was picked. The number picked did not in
DerKrebs [107]

Answer:

-19

Step-by-step explanation:

8 0
3 years ago
Hunter installed tiles on a floor with a length of 12 feet and a width of 9 feet in 712 hours. how many square feet of tiles can
grandymaker [24]
He can install 0.2 and .2 is rounded im sure
5 0
3 years ago
How to work out the medium in maths
Elis [28]

Answer:

To find the median you cross off the first few numbers and the last few until you get to the middle then when you get the middle number that will be your median

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the y value of the vertex of the function f(x)=-(x-3)(x+11)
AnnyKZ [126]

Answer:

49

Step-by-step explanation:

Because there is a minus sign infront of x-3, we can convert x-3 into the negative form:

- * x

- * -3

-x + 3

Which gives us:

(-x + 3)(x + 11)

Now expand the brackets with the formula:

(a + b)(c + d) = ac + ad + bc + bd

-x * x = -x²

-x * 11 = -11x

3 * x = 3x

3 * 11 = 33

-x² - 11x + 3x + 33

-x² - 8x + 33

The formula for finding the x coordinate of a vertex in a quadratic equation is:

x = \frac{-b}{2a}

Plug known variables in:

x = \frac{-(-8)}{2(-1)}

x = \frac{8}{-2}

x = -4

Now, to find the y coordinate, plug this variable back into the quadratic equation:

-x² - 8x + 33

y = -(-4^2) - (32) + 33\\y = -16 + 32 + 33\\\\

y = 49

So the y coordinate of the vertex is 49.

Hope this helps!

4 0
3 years ago
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