Which graph shows the solution to the following inequality?4d- 6 < 18 PLEASE HELP

Mathematics

2 answers:

kenny6666 [7]3 years ago

4 0

Answer:

answer a

Step-by-step explanation:

$4d-6$ < $18$

Let's isolate $d$ on one side of the equation. Ignore the inequality for now. We'll deal with that later.

$4d-6=18\\4d-6+6=18+6\\4d=24\\\frac{4d}{4}=\frac{24}{4}\\ d=6$

Now, I'm going to bring back the inequality or < symbol. I only removed it when simplifying and isolating $d$ , but if this confuses you, just do your math and keep the inequality there.

$d$ < $6$

On a number line, this would include every number less than $6$ , due to the < (less than) symbol. This disqualifies answers b and d because they are showing every number greater than $6$ . But, how do we decide between answers a and c?
If a line has point at its beginning, $6$ , then that means that every number less than or equal to [ ≤ ] 6 is being shown, but our equation just says less than [ < ] 6, so answer a is our correct answer.

dem82 [27]3 years ago

3 0

Answer A is the answer

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Marrrta [24]

Answer:

yes

Step-by-step explanation:

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3 years ago

Question part points submissions used as a science project, you drop a watermelon off the top of the empire state building, 320

Nataly [62]

We are given a watermelon dropped at free fall from a building 320 meters above the sidewalk. Superman is headed down at 30 meters per second. We are asked to determine how fast is the watermelon going when it passes Superman. To solve for the final velocity of the watermelon, we will use one of the kinematic equations (free fall):

vf = vi + a*t

where vf is the final velocity
vi is the initial velocity, zero
a is the acceleration, in this case, gravitational acceleration = 9.8m/s^2
t is time

we also need to set-up another equation using the distance:

d = vf + vi / 2 * t

(1) 320 m = vf * t /2

(2) vf = 9.8 m/s^2 * t

From here, we have two equations and two unknown, thus we can solve the problem by substitution.

8 0

3 years ago

If y=1/2 when x=2, find y when x=3, given that y varies directly with x

Lelu [443]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=\frac{1}{2}\\
x=2
\end{cases}\implies \cfrac{1}{2}=k2\implies \cfrac{1}{4}=k
\\\\\\
\boxed{y=\cfrac{1}{4}x}
\\\\\\
\textit{when x=3, what is \underline{y}?}\qquad y=\cfrac{1}{4}\cdot 3$