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seraphim [82]
3 years ago
13

Will 4in. 3in. and 5in. form a triangle?

Mathematics
1 answer:
lesya692 [45]3 years ago
8 0
Yes, there is a type of triangle called a "3 4 5 triangle" with side lengths 3, 4, and 5. 
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Write using only positive exponents. 16x^4z^4/36x-2yz^0
kolbaska11 [484]

Answer:

Step-by-step explanation:

16x^4y^-3z^4 / 36x^-2yz^0

16x^4y^-3z^4 = 16x^4z^4/y^3

36x^-2yz^0 = 36x^-2y(1) =36x^-2y = 36y/x^2

16x^4y^-3z^4 / 36x^-2yz^0

= (16x^4z^4/y^3) / (36y/x^2)

= 16x^4z^4/y^3 * x^2/36y  

= (4/9)x^6z^4/y^4

or another way

fist multiply it out

f(x) = 4x^(3/5) - x^(8/5)

now differentiate knowing d/dx(x^n) = n x^(n-1)

to get

4*(3/5) x^(-2/5) - 8/5 x^(3/5)

simplify to get

12/5/x^(2/5) -   8/5 x^(3/5)

If this is what your looking for please give me brainiest, i have done this problem in the past so i know how to solve it :)

5 0
3 years ago
At a high school, 85 students are enrolled in fine arts, 51 are enrolled in history, and 23 are enrolled in both subjects. How m
Jobisdone [24]

Fine arts= 85 students

History= 51 students

Both subjects=23 students

Only Fine arts=85-23=62 students

Only History=51-23=28 students

Hope you found it helpful.

4 0
3 years ago
what is an equation of the line that passes through the point (-3,1) and is parallel to the line 4x+3y=15?
guajiro [1.7K]

equation \: of \: required \: line \implies

4x + 3y + k = 0-----(1)

since \: it \: passes \: through \: ( - 3,1),

- 12 + 3 + k = 0

k = 9

substituting \: in \: k = 9 \: in \: (1),

we get,

4x + 3y + 9 = 0

hence \: the \: equation \: of \: the \: line \implies

\red{ \boxed{ \bold{4x + 3y + 9 = 0}}}

5 0
3 years ago
What is the approximate volume of this cone?
uysha [10]

Answer:

942

I wish you luck! :D

give person above me brainliest since he/she/non-binary answered first

8 0
3 years ago
the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant
Tamiku [17]

Answer:

The rate of change of the volume \frac{dV}{dt} when the height is 9 centimeters and the radius is 6 centimeters is 24\pi \:\frac{cm^3}{s}

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

  • \frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}
  • \frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}
  • The volume of a cone of radius r and height h is given by V=\frac{1}{3} \pi r^2 h

We want to find the rate of change of the volume \frac{dV}{dt} when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]

Substituting the values we know into the above formula:

\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}

5 0
4 years ago
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