All categories

3 years ago

(-5q^2 + 6q + 7) - (-q^2 + 4q)

Mathematics

2 answers:

Katen [24]3 years ago

7 0

Answer:

-4q^2+2q+7

Remove unecessary parenthesis

-5q^2+6q+7-(-q^2+4q)

when there is a - in front of an expression in parenthesis, change the sign of each term in the expression

-5q^2+6q+7+q^2-4q

collect like terms -5q^2 and q^2

-4q^2+6q+7-4q

-4q^2+2q+7

beks73 [17]3 years ago

5 0

Steps to solve:

(-5q^2 + 6q + 7) - (-q^2 + 4q)

~Distribute the left side

-5q^2 + 6q + 7 + q^2 - 4q

~Combine like terms

-4q^2 + 2q + 7

Best of Luck!

You might be interested in

Simplify: 11y-110/50-5y

alexandr1967 [171]

<h2>Answer:</h2> $\frac{11y-110}{50-5y}=-\frac{11}{5}$

<h2>Explanations:</h2>

Given the following expression show below;

$\frac{11y-110}{50-5y}$

Factor out the GCF from both the numerator and denominator

$\frac{11(y-10)}{5(10-y)}$

This can also be expressed as;

$\begin{gathered} \frac{11(-10+y)}{5(10-y)} \\ \frac{-11(10-y)}{5(10-y)} \end{gathered}$

Cancel out the common expression

$\frac{-11\cancel{(10-y)}}{5\cancel{(10-y)}}=-\frac{11}{5}$

Hence the simplified form of the expression is -11/5

7 0

1 year ago

Darrel divided 575 by 14 by using partial quotients. What is quotient and explain answer using numbers and words

RideAnS [48]

It at the top all you had to do was divided bot ways you will get that answers

4 0

3 years ago

1/6+1/12=<br><img src="https://tex.z-dn.net/?f=1%20%5Cdiv%206%20%2B%201%20%5Cdiv%2012" id="TexFormula1" title="1 \div 6 + 1 \div

erica [24]

$\frac{1}{6} + \frac{1}{12}$

We know that:

$\frac{a}{b} + \frac{c}{d} = \frac{a.d + b.c}{bd}$

So,

$\frac{1}{6} + \frac{1}{12} = \frac{1.12+6.1}{6.12}$

$\frac{12+6}{72}$

$\frac{18}{72}$

$\frac{9}{36}$

$\frac{3}{12}$

$\frac{1}{4}$

8 0

3 years ago

Sain has a student loan for $22,990. This loan has a simple interest rate of 5%. What is the amount of interest Sain will be cha

djyliett [7]

Answer:

3448.5

Step-by-step explanation:

I=PRT

I=22990×0.05×3

=$3448.5

4 0

3 years ago

Read 2 more answers

Tan x + sqrt(3) = - 2 tan x

Svet_ta [14]

9514 1404 393

Answer:

nπ -π/6 . . . for any integer n

Step-by-step explanation:

tan(x) +√3 = -2tan(x) . . . . . given

3tan(x) = -√3 . . . . . . . . . . . add 2tan(x)-√3

tan(x) = -√3/3 . . . . . . . . . . divide by 3

x = arctan(-√3/3) = -π/6 . . . . use the inverse tangent function to find x

This is the value in the range (-π/2, π/2). The tangent function repeats with period π, so the set of values of x that will satisfy this equation is ...

x = n·π -π/6 . . . . for any integer n

8 0

2 years ago