= 9n + 63
generate the first few terms using the recursive equation
f(1) = 72
f(2) = 72 + 9 = 81
f(3) = 81 + 9 = 90
f(4) = 90 + 9 = 99
the sequence is 72, 81, 90, 99, .....
This is an arithmetic sequence whose n th term formula is
= 
+ (n - 1 )d
where is the first term and d the common difference
d = 99 - 90 = 90 - 81 = 81 - 72 = 9 and = 72
= 72 + 9(n - 1) = 72 + 9n - 9 = 9n + 63 ← explicit formula
Answer:
13
Step-by-step explanation:
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Answer:
F=0 or (7/3)
Step-by-step explanation:
When F is 0, the equation reads -0(3(0)-7)=0. The outside 0 will multiply by everything and make it equal 0. When F is 7/3, the inside of the parenthesis read 3(7/3)-7. This equals 7-7. It'll end up being (7/3)0, which equals 0.
Answer: WY=4.4 mm
Step-by-step explanation:
WY=WX/2
WY=8.8/2
WY=4.4 mm
If you would like to solve y = x - 4 and 2 * x + y = 5, you can do this using the following steps:
y = x - 4
2 * x + y = 5
_____________
2 * x + (x - 4) = 5
2 * x + x = 5 + 4
3 * x = 9 /3
x = 9 / 3
x = 3
y = x - 4 = 3 - 4 = -1
The correct result would be x = 3 and y = -1.
