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3 years ago

How will the volume of the pyramid change if each side is multiplied by a factor of One-half?

Mathematics

2 answers:

mash [69]3 years ago

5 0

Answer:

I think the volume will be one-eighth times the volume

Step-by-step explanation:

blondinia [14]3 years ago

4 0

Answer:

The volume will be One-eighth times the volume.

Step-by-step explanation:

Well the formula for the volume of pyramid is,

$\frac{lwh}{3}$ ,

We can make the base length and width 6 units and the height 6 units too.

= 72

6 * 1/2 = 3

3*3*3

=18

18 / 3 = 6

So now we make a fraction 6/72,

3/36

1/12

1 ÷ 12 = .08333333

Thus,

the volume of the new pyramid is 1/8 times the volume.

Hope this helps :)

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F(x)=-4x^2+10x-8

vazorg [7]

Answer:

Step-by-step explanation:

a = - 4

b = 10

c = - 8

The discriminate is

D = b^2 - 4ac

D = 10^2 - 4*(-4)(-8)

D = 100 - 128

D = - 28 which is not a nice number

Because the Discriminate has a minus result, there are no real zeros.

6 0

3 years ago

Can someone help me please, explain in your own words. I'll give brainliest to the best and correct answer. Thank you (:

Elanso [62]

A) To factor a quadratic equation, standard form is the better form to use because it is easier to pull out a common factor from.

b) To graph a parabola, it is better to use vertex form so that you will know what point to graph as the vertex of the parabola.

c) To identify the vertex, maximum and minimum, it is better to use vertex form because the vertex form will give the values of the coordinates for the vertex. Then, you can use the equation to find the mininmum or maximum. If the graph is negative, it will have a maximum because it points downward infinitely. If the equation is positive, the graph will have a minimum because the graph points upward infinitely.

d) Standard form is easier to use when trying to solve using the quadratic formula because it is easier to see what the coeffiecnts and constants are to plug in for a b and c.

6 0

3 years ago

Suppose you are managing 16 employees, and you need to form three teams to work on different projects. Assume that all employees

valentina_108 [34]

Answer:

4380 ways

Step-by-step explanation:

We have to form 3 project of 16 employees, they tell us that the first project must have 5 employees, therefore we must find the number of combinations to choose 5 of 16 (16C5)

We have nCr = n! / (R! * (N-r)!)

replacing we have:

1st project:

16C5 = 16! / (5! * (16-5)!) = 4368 combinations

Now in the second project we must choose 1 employee, but not 16 but 11 available, therefore it would be to find the number of combinations to choose 1 of 11 (11C1)

2nd project:

11C1 = 11! / (1! * (11-1)!) = 11 combinations

For the third project we must choose 10 employees, but since we only have 10 available, we can only do a combination of this, since 10C10 = 1, therefore:

3rd project: 1 combination

The total number of combinations fro selecting 16 employees for each project would be:

4368 + 11 + 1 = 4380 combinations, that is, there are 4380 different ways of forming projects with the given conditions.

3 0

3 years ago

What is the volume of a hemisphere with a radius of 3.8in, rounded to the nearest tenth of a cubic inch

Pavel [41]

Answer: $114.9\ in.^3$