Answer:
A=152
K= -Ln(0.5)/14
Step-by-step explanation:
You can obtain two equations with the given information:
T(14 minutes) = 114◦C
T(28 minutes)=152◦C
Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

Applying the following property of exponentials numbers in (II):

Therefore
can be written as 
Replacing (I) in the previous equation:

Solving for k:
Subtracting 190 both sides, dividing by -76:

Applying the base e logarithm both sides:
Ln(0.5)= -14k
Dividing by -14:
k= -Ln(0.5)/14
Replacing k in (I) and solving for A:

Dividing by 0.5
A=152
Tim has 2 times as luke
t=2l
they have 29 goether
t+l=39
subsitute
2l+l=39
3l=39
divide by 3
l=13
subsitue
t=2l
t=2(13)
t=26
tim has 26 and luke has 13
I don't know how many marble Tim has but probably all of them since alll must die and then the marbles go to Time
Answer:
it is 358
Step-by-step explanation:
Hope this helped have an amazing day!
Let us add consecutive odd numbers and try to find any relationship.
1. 1
2. 1+3 = 4 ( square of 2 i.e
)
3. 1+3+5 = 9 (
)
4. 1+3+5+7 = 16 (
)
5. 1+3+5+7+9 = 25 (
)
6. 1+3+5+7+9+11 = 36 (
)
7. 1+3+5+7+9+11+13 = 49 (
)
If we notice, the sum of the consecutive odd integers in each case is equal to the square of the place where it lies. For example, the sum of numbers in seventh place is equal to
. The sum of the numbers in the fifth line is equal to
.
2 1/4 * 1 3/8 = 3 3/32 or 99/32