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ryzh [129]
2 years ago
7

What is the area of the figure? Enter your answer in the box. 400 in²

Mathematics
2 answers:
lesya692 [45]2 years ago
7 0

Answer:

should be 112 cm^2

Step-by-step explanation:

10cm*10cm+(1/2(4*6)

dem82 [27]2 years ago
5 0

Answer:

112

Step-by-step explanation:

To make this easier we can pull apart the two know shapes which is the square and triangle

the formula to find the area square is length x width

so 10 x 10=100 this is the area of the triangle

the picture doesn't show the measurements of the triangle but we can still find it

16 in goes from the top of the triangle to the bottom of the square and we know the right side of the square is 10 in so to find the length of the left side of the triangle we can subtract 10 from 16 which is 6.

now we need to find the bottom part of the triangle we can see that it measures 6 in to the right of the triangle and we know that the side of the square is 10 in so all we do is subtract 6 from 10 and you get 4

the formula to find the area of a triangle is height x base divided by 2

so 6 x 4 divided by 2 is 12

now we know the area of the triangle and square is 12 and 100 so we add these together to get 112

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stepladder [879]
Is there a picture or something?
7 0
2 years ago
Help and explain explain !!!!!!!!!!
tigry1 [53]

Answer:

x=-1\text{ or }x=11

Step-by-step explanation:

For a=|b|, we have two cases:

\begin{cases}a=b,\\a=-b\end{cases}

Therefore, for 18=|15-3x|, we have the following cases:

\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}

Solving, we have:

\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}.

Therefore,

\implies \boxed{x=-1\text{ or }x=11}

3 0
2 years ago
What is the answer to x-1=-5-x
maria [59]

Answer:

x=-2

Step-by-step explanation:

We have the equation x-1=-5-x

In order to solve for x, we need to get all of the x's to one side and everything else to the opposite side

x-1=-5-x

First, we can add 1 to each side

x=-4-x

Now, we can add x to each side

2x=-4

Next, we can divide each side by 2

x=-2

And here is our answer.

8 0
3 years ago
Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)
ELEN [110]

Question:

Find the point (,) on the curve y = \sqrt x that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})

Step-by-step explanation:

y = \sqrt x can be represented as: (x,y)

Substitute \sqrt x for y

(x,y) = (x,\sqrt x)

So, next:

Calculate the distance between (x,\sqrt x) and (3,0)

Distance is calculated as:

d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}

So:

d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}

d = \sqrt{(x-3)^2 + (\sqrt x)^2}

Evaluate all exponents

d = \sqrt{x^2 - 6x +9 + x}

Rewrite as:

d = \sqrt{x^2 + x- 6x +9 }

d = \sqrt{x^2 - 5x +9 }

Differentiate using chain rule:

Let

u = x^2 - 5x +9

\frac{du}{dx} = 2x - 5

So:

d = \sqrt u

d = u^\frac{1}{2}

\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}

Chain Rule:

d' = \frac{du}{dx} * \frac{dd}{du}

d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}

d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}

d' = \frac{2x - 5}{2\sqrt u}

Substitute: u = x^2 - 5x +9

d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}

Next, is to minimize (by equating d' to 0)

\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0

Cross Multiply

2x - 5 = 0

Solve for x

2x  =5

x = \frac{5}{2}

Substitute x = \frac{5}{2} in y = \sqrt x

y = \sqrt{\frac{5}{2}}

Split

y = \frac{\sqrt 5}{\sqrt 2}

Rationalize

y = \frac{\sqrt 5}{\sqrt 2} *  \frac{\sqrt 2}{\sqrt 2}

y = \frac{\sqrt {10}}{\sqrt 4}

y = \frac{\sqrt {10}}{2}

Hence:

(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})

3 0
3 years ago
Solve by elimination:<br> 2x + 4y = 34<br> x+4y = 27<br> A (7,-5)<br> B (6,6)<br> (7,5)<br> (5,7)
julsineya [31]

Answer:

(7,5)

Step-by-step explanation:

{2x + 4y = 34

{4y = 27 - x

2x + 27 - x = 34

x=7

4y = 27 - 7

y = 5 so the answer is ( 7,5)

3 0
3 years ago
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