Ask question

Ask question

All categories

3 years ago

11

10 points. The diameters of two circles are in the ratio of 2:3. Find the area of the smaller circle if the area of the larger i

s 63π square meters.

1 answer:

AnnyKZ [126]3 years ago

3 0

$63 \times \frac{2}{3} = \frac{63 \times 2}{3} = \frac{126}{3} = 42 \\$

The area of the smaller circle is

$42\pi \: square \: meters$

You might be interested in

Eddie has saved up $45 to purchase a new camera from the local store. The sales tax in his county is 7% of the sticker price. Wr

NARA [144]

tax gets added to the price of the camera

so the equation is:

x + 0.07x = 45; x = $42.06

3 0

3 years ago

Four brother each bought two hotdogs and a bag of chips at the football

jeyben [28]

Answer:

A-$1.65

Step-by-step explanation:

You multiply 1.25 by 4 because each brother bought a bag of chips. Then you subtract that by the total and get $13.20 you divide that by 8 hot dog because each brother got 2 hot dogs. By dividing 8 by the left over amount from subtracting the chips you get how much each hot dog is worth.

8 0

2 years ago

I’m doing edg unit test what is the answer to. Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping?

sertanlavr [38]

Answer:

(4x + 1)(x² - 2)

Step-by-step explanation:

Given

4x³ + x² - 8x - 2 ( factor the first/second and third/fourth terms )

= x²(4x + 1) - 2(4x + 1) ← factor out (4x + 1) from each term

= (4x + 1)(x² - 2)

6 0

2 years ago

given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

6 0

3 years ago

Plz help me I will mark u brainiest

Likurg_2 [28]

Answer:

quadrant one

Hope this helps

5 0

3 years ago