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antiseptic1488 [7]
2 years ago
13

A particular computer takes 11 minutes to download a 33-minute TV show. How long will it take the computer to download a 2-hour

movie?
It will take the computer minutes to download a 2-hour movie.
(Type an integer or a decimal.)
Mathematics
2 answers:
slava [35]2 years ago
8 0

Answer:

i got 42 minutes

Step-by-step explanation:

olga55 [171]2 years ago
4 0

Answer:

40 Minutes

Step-by-step explanation:

1 Min In real life= 3 Minutes in downloaded movie

10 Min in real life= 30 Minutes in downloaded movie

20 Min in real life= 60 Minutes in downloaded movie

30 Min in real life= 90  Minutes in downloaded movie

40 Min in real life= 120 Minutes in downloaded movie

Hopefully that helps! Also can I get Brainliest

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Answer:

46.6 mph

Step-by-step explanation:

1 Kph is .6213 mph

6 0
3 years ago
Approximately what portion of the circle is shaded blue?<br><br> A. 2/3<br> B. 2/10 C.2/5
Nuetrik [128]
C) closest to 2/5.
2/3 is bigger than half 2/10 would be like less than 1/4
3 0
2 years ago
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Cone W has a radius of 8 cm and a height of 5 cm. Square pyramid X has the same base area and height as cone W. Paul and Manuel
sergij07 [2.7K]

This question is incomplete because it lacks the appropriate attachment containing the argument of Paul and Manuel

Kindly find attached the appropriate attachment necessary to solve this question.

The attachment was sourced online

Answer:

a) Paul's argument is correct, Manuel used the wrong formula to find the volume of square pyramid X

Step-by-step explanation:

From the above question, we are given two shapes: Cone W and Square Pyramid

Cone W: Radius = 8cm, Height = 5cm

Volume of a Cone = 1/3 πr²h

Where π = 3.14

Volume of Cone X = 1/3 × 3.14 × 8² × 5

= 334.93cm³

For Square pyramid X

Volume = 1/3 × Base Area × Height

Base Area of Cone W = Base Area of square pyramid X = πr²

Where π = 3.14

Base area = 3.14 × 8² = 200.96cm²

Height of Square pyramid X = Height of Cone W = 5cm

Volume of Square pyramid = 1/3 ×200.96cm² × 5cm

= 334.93cm³

Therefore, from my above calculation and compared with the arguments of Paul and Manuel, Option a) "Paul's argument is correct, Manuel used the wrong formula to find the volume of square pyramid X" is the correct option.

The reason why is because the correct formula for the volume of a square pyramid = 1/3 × Base area × Height

This was the formula Paul used.

Manuel on the other hand used the formula: Base Area × Height to find the volume of cone W. This formula is wrong.

Option a, is the correct answer.

4 0
3 years ago
What is the minimum number of bits required to store each binary string of length 50? (b) what is the minimum number of bits req
antiseptic1488 [7]
In order to answer the above question, you should know the general rule to solve these questions.
The general rule states that there are 2ⁿ subsets of a set with n number of elements and we can use the logarithmic function to get the required number of bits.
That is: 
log₂(2ⁿ) = n number of <span>bits
</span>
a). <span>What is the minimum number of bits required to store each binary string of length 50?
</span>
Answer: In this situation, we have n = 50. Therefore,  2⁵⁰ binary strings of length 50 are there and so it would require:

                                                     log₂(2⁵⁰) <span>= 50 bits.

b). </span><span>what is the minimum number of bits required to store each number with 9 base of ten digits?
</span>
Answer: In this situation, we have n = 50. Therefore, 10⁹ numbers with 9 base ten digits are there and so it would require:

                                                     log2(109)= 29.89 
<span>                                                                     = 30 bits. (rounded to the nearest                                                                                                                        whole #)

c).  </span><span>what is the minimum number of bits required to store each length 10 fixed-density binary string with 4 ones?
</span>
Answer: There is (10,4) length 10 fixed density binary strings with 4 ones and
so it would require:
                                                     log₂(10,4)=log₂(210) = 7.7
                                                                    = 8 bits. (rounded to the nearest                                                                                                                        whole #)
4 0
2 years ago
What are the different ways to write multiplication in math
elena-14-01-66 [18.8K]

Answer:

Different ways to write multiplication include:

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Step-by-step explanation:

I hope this helps!

8 0
2 years ago
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