Answer: D) csc (2π/3)
<u>Step-by-step explanation:</u>
2π/3 is in Quadrant II
Quadrant II has a negative x-value and a positive y-value.
x-values are: cos & sec
y-values are: sin & csc
tan = y/x so will be negative in Quadrant II
A) sec = -
B) tan = -
C) cos = -
D) csc = + this works!
Answer:
In an equilateral triangle, all three sides are the same length. An equilateral triangle is always equiangular. In an isosceles triangle, two sides are the same length. An isosceles triangle may be right, obtuse, or acute.
Step-by-step explanation:
Answer:
6 is the ans
Step-by-step explanation:
Write a Pythagorean triplet whose one member is.
2m, m 2 − 1 , m 2 + 1 \mathrm{m}^{2}-1,
mathrm{m}^{2}+1 m2−1,m2+1 is a Pythagorean triplet.
∴ (6, 8, 10) is a Pythagorean triplet.
Answer:
h = 3V/(πr²)
Step-by-step explanation:
You are asked to solve a one-step linear equation for h.
<h3>Solution</h3>
The "one step" is to divide by the coefficient of h.
![V=\dfrac{1}{3}\pi r^2h\qquad\text{given}\\\\\dfrac{V}{\dfrac{1}{3}\pi r^2}=\dfrac{\dfrac{1}{3}\pi r^2h}{\dfrac{1}{3}\pi r^2}\qquad\text{divide by the coefficient of h}\\\\\boxed{h=\dfrac{3V}{\pi r^2}}\qquad\text{simplify}](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7D%5Cpi%20r%5E2h%5Cqquad%5Ctext%7Bgiven%7D%5C%5C%5C%5C%5Cdfrac%7BV%7D%7B%5Cdfrac%7B1%7D%7B3%7D%5Cpi%20r%5E2%7D%3D%5Cdfrac%7B%5Cdfrac%7B1%7D%7B3%7D%5Cpi%20r%5E2h%7D%7B%5Cdfrac%7B1%7D%7B3%7D%5Cpi%20r%5E2%7D%5Cqquad%5Ctext%7Bdivide%20by%20the%20coefficient%20of%20h%7D%5C%5C%5C%5C%5Cboxed%7Bh%3D%5Cdfrac%7B3V%7D%7B%5Cpi%20r%5E2%7D%7D%5Cqquad%5Ctext%7Bsimplify%7D)
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<em>Additional comment</em>
The equation is "linear" because the variable of interest is h. It has an exponent (degree) of 1. The other "variables" are treated as though they were constants. The equation is conceptually no different from ...
2 = (5/3)h
which you solve by dividing by 5/3 (or multiplying by 3/5).
Answer:
2/10ths?? idk
Step-by-step explanation: