Answer:
There are 59.66 inches in the circumference of the large pizza.
Step-by-step explanation:
It is given that:
Diameter of Joe's large pizza = 19 inches
Diameter = 2r
2r = 19
Circumference of large pizza = 2πr = 2r * π
Circumference of large pizza = 19*3.14
Circumference = 59.66 inches
Therefore,
There are 59.66 inches in the circumference of the large pizza.
A 100% increase would be 18 so you just have to divide until you get the number added so from 9 to 13 is a increase of 4 so that would be around 44.44% repeating.
Answer:
Step-by-step explanation:
Given
Area of a floor = 2040ft²
If Its length is 36ft. longer than its width, then L = W+36
Area = LW
L is the length
W is the width
A < W(W+36)
2040 < W²+36W
0<W²+36W-2040
W²+36W-2040 >0
W = -36±√36²-4(-2040)/2
W = -36±√1296+8160)/2
W = -36±√9456/2
W = -36±97.25/2
W = -36+97.25/2
W = 61.24/2
W > 30.62ft
Since L = W+36
L > 30.62+36
L > 66.62ft
The width of the floor is 30.62ft
The length is 66.62ft
The mathematical sentence would represent the given situation is the width is greater than 30.62ft while the length must be greater than 66.62ft
The possible dimension of the floor is 31ft by 67 ft
The possible areas is 31*67 = 2077ft²
It won't be realistic to get an area of 144sqft because the initial area is greater than 144. Hence the feasible area will be greater than 2040ft²
Answer:
$1556.25
Step-by-step explanation:
Answer:
yes Bro it is correct ar u writing an exam