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Nostrana [21]
3 years ago
7

What is the value of X in 1.2÷0.3= X÷0.4

Mathematics
2 answers:
sashaice [31]3 years ago
8 0

1.2 \div .3 = 4
4 = x \div .4
multiply both sides by .4 to isolate the x variable.

4 \times .4 = x

x = 1.6
Anna007 [38]3 years ago
8 0
X=1.6 because you have to divide 0.3 on each side then calculate the math and equal to x=1.6
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Write the quadratic equation y= x^2 -6x = 7 in vertex form.
lapo4ka [179]

Answer:

(x - 3)² - 16 = 0

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Subtract 7 from both sides

x² - 6x + 7 = 0 ← in standard form

with a = 1, b = - 6

Given a quadratic in standard form then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a} = - \frac{-6}{2} = 3

Substitute x = 3 into the equation for y

y = 3² - 6(3) - 7 = 9 - 18 - 7 = - 16 ⇒ (h, k) = (3, - 16)

y = (x - 3)² - 16 = 0

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3 years ago
Find an equation of a plane that satisfies the given conditions
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The conditions are needed to be able to answer the question 
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3 years ago
The difference between homogeneous and heterogeneous mixtures is that chemical bonds are formed in homogeneous mixtures.
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The answer would be false.
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3 years ago
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A map of the United States is displayed in the classroom with a scale of
Marysya12 [62]

Answer:

27.5 cm

Step-by-step explanation:

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Suppose that in a senior college class of 500500 ​students, it is found that 179179 ​smoke, 228228 drink alcoholic​ beverages, 1
olga2289 [7]

Answer: a) 0.16, b) 0.058, and c) 0.856.

Step-by-step explanation:

Since we have given that

Number of students = 500

Number of students smoke = 179

Number of students drink alcohol = 228

Number of students eat between meals = 119

Number of students eat between meals and drink alcohol = 59

Number of students eat between meals and smoke = 72

Number of students engage in all three = 30

a) Probability that the student smokes but does not drink alcohol is given by

P(S-A)=P(S)-P(S\cap A)\\\\P(S-A)=\dfrac{179}{500}-\dfrac{99}{500}\\\\P(S-A)=\dfrac{179-99}{500}\\\\P(S-A)=\dfrac{80}{500}\\\\P(S-A)=0.16

b) eats between meals and drink alcohol but does not smoke.

P((M\cap A)-S)=P(M\cap A)-P(M\cap S\cap A)\\\\P((M\cap A)-S)=\dfrac{59}{500}-\dfrac{30}{500}\\\\P((M\cap A)-S)=\dfrac{59-30}{500}\\\\P((M\cap A)-S)=\dfrac{29}{500}\\\\P((M\cap A)-S)=0.058

c) neither smokes nor eats between meals.

P(S'\cap M')=1-P(S\cup M)\\\\P(S'\cap M')=1-\dfrac{72}{500}\\\\P(S'\cap M')=\dfrac{500-72}{500}\\\\P(S'\cap M')=\dfrac{428}{500}=0.856

Hence, a) 0.16, b) 0.058, and c) 0.856.

5 0
3 years ago
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