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3 years ago

Kate runs 3 miles a day. If she runs every day for a year (365 days), how much more or less than 1,000 miles will she run?

Mathematics

2 answers:

Alisiya [41]3 years ago

8 0

Answer:

it's D because 3*365 is 1095 which is 95 more than 1000

Vera_Pavlovna [14]3 years ago

5 0

Answer:

You would take 3*365 to figure out how many miles Kate runs

3*365=1,095

you would then subtract 1,095-1,000

1,095-1,000=95,

So Kate runs 95 miles more

Step-by-step explanation:

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Container 1 has 8 items, 3 of which are defective. Container 2 has 5 items, 2 of which are defective. If one item is drawn from

e-lub [12.9K]

Answer:

The required probability is $\frac{19}{40}$

Step-by-step explanation:

The probability of obtaining a defective item from container 1 is $P(E_1)=\frac{3}{8}$

The probability of obtaining a good item from container 1 is $P(E_1)=\frac{5}{8}$

The probability of obtaining a defective item from container 2 is $P(E_1)=\frac{2}{5}$

The probability of obtaining a good item from container 2 is $P(E_1)=\frac{3}{5}$

The cases of the event are

1)Defective item is drawn from container 1 and good item is drawn from container 2

2)Defective item is drawn from container 2 and good item is drawn from container 1

Thus the required probability is the sum of above 2 cases

$P(Event)=\frac{3}{8}\times \frac{3}{5}+\frac{5}{8}\times \frac{2}{5}=\frac{19}{40}$

4 0

3 years ago

The weight of an object on the moon varies directly with its weight on the earth. If an object weighing 95 lbs on the moon weigh

Luda [366]

ANSWER

450lb

EXPLANATION

If the weight, m of an object on the moon varies directly as the weight of an object e, on the earth, then we can write the mathematical statement,.
$m \propto \: e$
We introduce the constant of proportionality to obtain,

$m = ke$

When, m=95, e=570,

This implies that,

$95 = 570k$
$k = \frac{95}{570}$

$k = \frac{1}{6}$

The equation now becomes,

$m = \frac{1}{6} e$

We want to find e, when m=2700,

$m = \frac{1}{6} \times 2700$

$m =450lb$

8 0

3 years ago

2:x and 12:18 a-3, b-4, c-6

nirvana33 [79]

The Corrected Problem is :

2:x and 12:18 identify the value of x that makes each pair of ratios equivalent .

Solution:

If a pair of Ratios are equivalent then we can write

$\frac{2}{x}=\frac{12}{18}\\ \\ \text{Simplify we get}\\ \\ 12x=36\\ \\ \text{Divide both the sides by 12 we get}\ \\ \\ \frac{12x}{12}=\frac{36}{12}\\ \\ x=3\\ \\ \text{Hence the required value of x is 3}\\$