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3 years ago

2x ≤ 12 Select the appropriate response A2x ≤ 12 B)x≤4 C)x≤6 D)x ≤ 10

Mathematics

1 answer:

Monica [59]3 years ago

8 0

Answer:

c x ≤ 6

Step-by-step explanation:

2x ≤ 12

Divide each side by 2

2x/2 ≤ 12/2

x ≤ 6

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Three equal ratios to 6/7

Rashid [163]

12/14 , 18/21 , 24/28

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3 years ago

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Valeria has a new beaded necklace. 18 out of the 20 beads on the necklace are blue. What percentage of beads on Valeria's neckla

ANTONII [103]

Answer:

nFtmamtamysktakysykzylyu

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3 years ago

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in a park of 30 people, 15 were walking, 7 were playing and 6 were just running. find the percentage of people who were not doin

monitta

Answer:

6.67

Step-by-step explanation:

Because in the park there are 30 people OK

15 were walking

7 were playing

6 were running.

15 + 7 + 6=28

Meaning there are still 2 people left so that is 6.67 =% of the people.

Hope it helps have a great afternoon:)

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2 years ago

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A number is double of another number. If the difference of the numbers is twenty find the numbers

Ivanshal [37]

Answer:

20 and 40

Step-by-step explanation:

20 doubled is 40

The difference is 20

Hope this helps! :)

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3 years ago

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The function f(x) = 2x2 + 3x + 5, when evaluated, gives a value of 19. What is the function’s input value?

goldenfox [79]

$f(x)=\quad 2{ x }^{ 2 }+3x+5$

Let's called the input 'z'

When we plug 'z' in the function we get ;

$f(z)=\quad 2{ z }^{ 2 }+3z+5$

And we know that, this is equal to 19, so ;

$2{ z }^{ 2 }+3z+5=\quad 19$

Let's rearrange the equation.

$2{ z }^{ 2 }+3z+5=\quad 19\\ \\ 2{ z }^{ 2 }+3z=\quad 19-5\\ \\ 2{ z }^{ 2 }+3z=\quad 14\\ \\ 2{ z }^{ 2 }+3z-14=\quad 0$

So we have a quadratic equation here.

We'll use this formula to solve it :

$\frac { -b\pm \sqrt { { b }^{ 2 }-4ac } }{ 2a }$

The formula is used in equation formed like this :

$a{ x }^{ 2 }+bx+c=0$

In our equation,

a=2 , b=3 and c=-14

Let's plug in the values in the formula to solve,

$a=2\quad b=3\quad c=-14\\ \\ \frac { -3\pm \sqrt { 9-(4\cdot 2\cdot -14) } }{ 4 } \\ \\ \frac { -3\pm \sqrt { 9-(-112) } }{ 4 } \\ \\ \frac { -3\pm \sqrt { 9+112 } }{ 4 } \\ \\ \frac { -3\pm \sqrt { 121 } }{ 4 } \\ \\ \frac { -3\pm 11 }{ 4 }$

So,

$z=\quad \frac { -3+11 }{ 4 } \quad ,\quad \frac { -3-11 }{ 4 } \\ \\ z=\quad \frac { 8 }{ 4 } \quad ,\quad \frac { -14 }{ 4 } \\ \\ z=\quad 2,\quad -\frac { 7 }{ 2 }$

So the input can be both, 2 and $-\frac{7}{2}$

8 0

3 years ago