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kobusy [5.1K]
4 years ago
6

At Fairprice supermarket branches, they provide free fish cleaning services if fish were bought at their premises. Currently, on

e employee is employed for this task at each of its branch. Based on their observation, on average, every 8 minutes there is a request for such service. A recent customer service quality survey has indicated that customers’ desired time for this service (including fish’ waiting and cleaning) should be no more than 5 minutes on average. The management wants to know what should be the maximum mean cleaning time the employee should strive for in order to meet customers’ expectation.
Could you please help them? (Assume all CV=1) Choose the closest answer.

a) 2.5 minutes
b) 3.5 minutes
c) 4.5 minutes
d) 5.5 minutes
e) 6.5 minutes
Business
1 answer:
Nina [5.8K]4 years ago
5 0

Answer:

4.5minutes

Explanation:

The best mean minutes for fish waiting and cleaning is 4.5 minutes.

As said in the question that, clients request for this service every 8minutes, and it is a worker that is in charge of this service per branch, this means that if the worker is using 4.5 minutes to attend to a client, he or she will still have another 3.5 minutes to prepare for another customer. And this will definitely make the job easier for him or her, which means the worker will not be bombarded with request. And this will make him or her to render the best service to the customers.

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The safety stock formula with standard deviation is more complicated but also more accurate.

Safety stock = desired service level × standard deviation of lead time × demand average

Safety stock = ( 93÷100) ×  2.9 × 5.9 =  15. 91  or 16 gallons (rounded off)  

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= (5.9 x 2) + 15. 91 = 11.8 + 15.91 = 27.71 or 28 (rounded off)

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