Answer: (C) <em>bottom left graph</em>
<u>Step-by-step explanation:</u>
Create a table for each interval:
![\begin {array}{c|l}\underline{\ x\ }&\underline{(x+2)^2=y}\\ -3&(-3+2)^2=1\\-2&(-2+2)^2=0\\-1&(-1+2)^2=1\quad \text{ope n dot}}\\\end{array}\\\\\text{Note: All of the graphs satisfy these coordinates}\\\\\begin {array}{c|l}\underline{\ x\ }&\underline{(|x|+1=y}\\ -1&|-1|+1=2\quad \text{closed dot}}\\0&|0|+1=1\\1&|1|+1=2\quad \text{closed dot}}\\\end{array}\\\\\text{Note: Graph C is the only graph that satisfies these coordinates}](https://tex.z-dn.net/?f=%5Cbegin%20%7Barray%7D%7Bc%7Cl%7D%5Cunderline%7B%5C%20x%5C%20%7D%26%5Cunderline%7B%28x%2B2%29%5E2%3Dy%7D%5C%5C%20-3%26%28-3%2B2%29%5E2%3D1%5C%5C-2%26%28-2%2B2%29%5E2%3D0%5C%5C-1%26%28-1%2B2%29%5E2%3D1%5Cquad%20%5Ctext%7Bope%20n%20dot%7D%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5C%5C%5Ctext%7BNote%3A%20All%20of%20the%20graphs%20satisfy%20these%20coordinates%7D%5C%5C%5C%5C%5Cbegin%20%7Barray%7D%7Bc%7Cl%7D%5Cunderline%7B%5C%20x%5C%20%7D%26%5Cunderline%7B%28%7Cx%7C%2B1%3Dy%7D%5C%5C%20-1%26%7C-1%7C%2B1%3D2%5Cquad%20%5Ctext%7Bclosed%20dot%7D%7D%5C%5C0%26%7C0%7C%2B1%3D1%5C%5C1%26%7C1%7C%2B1%3D2%5Cquad%20%5Ctext%7Bclosed%20dot%7D%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5C%5C%5Ctext%7BNote%3A%20Graph%20C%20is%20the%20only%20graph%20that%20satisfies%20these%20coordinates%7D)
No need to create the table for the last interval.
The equation that allows us to find the value of N is 12N + 8 = 123.
<h3><u /></h3><h3><u>Equations</u></h3>
Given that at a wedding reception, an equal number of guests were seated at each of 12 large tables, and 8 members of the wedding party were seated at the main table, and the total number of people at the reception, including the bride and groom , was 123, to determine what equation could you use to find the value of N if this letter represents the number of people at large tables, the following calculation must be performed:
- 12N + 8 = 123
- 12N = 123 - 8
- 12N = 115
- N = 115 / 12
- N = 9,583
Now, despite the fact that the problem is poorly formulated and the number N is not an integer, the equation that allows us to find the value of N is 12N + 8 = 123.
Learn more about equations in brainly.com/question/2263981
In fraction form, it’s 213333^4/ 10,000^4
5/100 means that the 5 is in the hundredths place so the decimal is: .05
Answer:
Given that,
An amount of $23,000 is borrowed for 11 years at 6.75% interest, compounded annually.
To find the Amount paid back after 11 years.
Explanation:
we know that,
The formula to find the,
Amount after n years of interest rate r% compounded annually is,
![A=P(1+\frac{r}{100})^n](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7B100%7D%29%5En)
where P is the initial amount.
Here, we have that,
P=$23,000
r=6.75
n=11
Substitute the values we get,
![A=23000(1+\frac{6.75}{100})^{11}](https://tex.z-dn.net/?f=A%3D23000%281%2B%5Cfrac%7B6.75%7D%7B100%7D%29%5E%7B11%7D)
Solving this we get,
![A=23000(1+0.0675)^{11}](https://tex.z-dn.net/?f=A%3D23000%281%2B0.0675%29%5E%7B11%7D)
![A=23000(1.0675)^{11}](https://tex.z-dn.net/?f=A%3D23000%281.0675%29%5E%7B11%7D)
![A=23000(2.05138)](https://tex.z-dn.net/?f=A%3D23000%282.05138%29)
![A=47181.805](https://tex.z-dn.net/?f=A%3D47181.805)
Round to the nearest dollar.
![A=47181.805\approx47182](https://tex.z-dn.net/?f=A%3D47181.805%5Capprox47182)
Answer is: Amount paid back is $47182 after 11 years