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Marrrta [24]
2 years ago
10

PLS HELP For the fourth week of April, Linda Allen worked 45 hours. Linda earns $12.80 an hour. Her employer pays overtime for a

ll hours worked in excess of 40 hours per week and pays 1.5 times the hourly rate for overtime hours. Calculate the following for the fourth week of April (round your responses to the nearest cent if necessary):
Mathematics
2 answers:
chubhunter [2.5K]2 years ago
7 0

608


Step-by-step explanation:

12.8 × 1.5 is 19.2 so 19.2 × 5 is 96 dollars in overtime and then 12.8 × 40 is 512 so 512 + 96 is 608


prohojiy [21]2 years ago
5 0

Answer:

$12.80 x40 + $512.00

1.5 hourly rate = $12.80 +$6.40 = 19.20 x 5 hrs. = $96.00

Fourth week of April $512.00 + $96.00 = $608.00

Step-by-step explanation:


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Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.
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To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>
  • x^ax^b = x^{(a+b)}
  • \dfrac{x^a}{x^b} = x^{(a-b)}
  • (a^a)^b =x^{(a\times b)}
  • (xy)^a = x^ay^a
  • x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4

The solution of the expression is \dfrac{4x^4}{y^6}.

<h2>Explanation</h2>

Given to us

  • (16x^8y^{12})^{\frac{1}{2}}

Solution

We know that 16 can be reduced to 2^4,

=(2^4x^8y^{12})^{\frac{1}{2}}

Using identity (xy)^a = x^ay^a,

=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}

Using identity (a^a)^b =x^{(a\times b)},

=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})

Solving further

=2^2x^4y^{-6}

Using identity \dfrac{x^a}{x^b} = x^{(a-b)},

=\dfrac{2^2x^4}{y^6}

=\dfrac{4x^4}{y^6}

Hence, the solution of the expression is \dfrac{4x^4}{y^6}.

Learn more about Exponentiation:

brainly.com/question/2193820

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