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Marrrta [24]
2 years ago
10

PLS HELP For the fourth week of April, Linda Allen worked 45 hours. Linda earns $12.80 an hour. Her employer pays overtime for a

ll hours worked in excess of 40 hours per week and pays 1.5 times the hourly rate for overtime hours. Calculate the following for the fourth week of April (round your responses to the nearest cent if necessary):
Mathematics
2 answers:
chubhunter [2.5K]2 years ago
7 0

608


Step-by-step explanation:

12.8 × 1.5 is 19.2 so 19.2 × 5 is 96 dollars in overtime and then 12.8 × 40 is 512 so 512 + 96 is 608


prohojiy [21]2 years ago
5 0

Answer:

$12.80 x40 + $512.00

1.5 hourly rate = $12.80 +$6.40 = 19.20 x 5 hrs. = $96.00

Fourth week of April $512.00 + $96.00 = $608.00

Step-by-step explanation:


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At the Souvenir Shop, gemstone souvenirs cost $11.60 for 5. Which proportion can be used to find the cost of just 1 gemstone?
Natasha2012 [34]

Answer:

see below

Step-by-step explanation:

$11.60 for $5

1. Find the rate.

$11.60 divided by $5= $2.32

2. 1 gemstone= $2.32

Your anwser should be 1 over $2.32 or $2.32 over 1 depending on how you want it.

5 0
3 years ago
Which of the following pairs of numbers contains like fractions? A. 5⁄6 and 10⁄12 B. 3⁄2 and 2⁄3 C. 3 1⁄2 and 4 4⁄4 D. 6⁄7 and 1
ElenaW [278]
<h2>Hello!</h2>

The answers are:

A.

\frac{5}{6} and \frac{10}{12}

D.

\frac{6}{7} and 1\frac{5}{7}

<h2>Why?</h2>

To find which of the following pairs of numbers contains like fractions, we must remember that like fractions are the fractions that share the same denominator.

We are given two fractions that are like fractions. Those fractions are:

Option A.

\frac{5}{6} and \frac{10}{12}

We have that:

\frac{10}{12}=\frac{5}{6}

So, we have that the pairs of numbers

\frac{5}{6}

and

\frac{5}{6}

Share the same denominator, which is equal to 6, so, the pairs of numbers contains like fractions.

Option D.

\frac{6}{7} and 1\frac{5}{7}

We have that:

1\frac{5}{7}=1+\frac{5}{7}=\frac{7+5}{7}=\frac{12}{7}

So, we have that the pair of numbers

\frac{6}{7}

and

\frac{12}{7}

Share the same denominator, which is equal to 7, so, the pairs of numbers constains like fractions.

Also, we have that the other given options are not like fractions since both pairs of numbers do not share the same denominator.

The other options are:

\frac{3}{2},\frac{2}{3}

and

3\frac{1}{2},4\frac{4}{4}

We can see that both pairs of numbers do not share the same denominator so, they do not contain like fractions.

Hence, the answers are:

A.

\frac{5}{6} and \frac{10}{12}

D.

\frac{6}{7} and 1\frac{5}{7}

Have a nice day!

3 0
3 years ago
If the length of a rectangle is 3 and the width is 2, the length of the diagonal is a 13 b 5 c √5 d √13
trasher [3.6K]

Answer:

The length of the rectangle is 12cm and the area of the rectangle is 60cm2.

Explanation:

By definition, the angles of a rectangle are right. Therefore, drawing a diagonal creates two congruent right triangles. The diagonal of the rectangle is the hypotenuse of the right triangle. The sides of the rectangle are the legs of the right triangle. We can use the Pythagorean Theorem to find the unknown side of the right triangle, which is also the unknown length of the rectangle.

Recall that the Pythagorean Theorem states that the sun of the squares of the legs of a right triangle is equal to the square of the hypotenuse. a2+b2=c2

52+b2=132

25+b2=169

25−25+b2=169−25

b2=144

√b2=√144

b=±12

Since the length of the side is a measured distance, the negative root is not a reasonable result. So the length of the rectangle is 12 cm.

The area of a rectangle is given by multiplying the width by the length.

A=(5cm)(12cm)

A=60cm2

3 0
2 years ago
Which of the following statements is not​ true? A. If the probability of an event occurring is​ 1.5, then it is certain that eve
yawa3891 [41]

Answer:

Therefore, we conclude that the statement in (A) is incorrect.

Step-by-step explanation:

We have the following sentences:

A) If the probability of an event occurring is​ 1.5, then it is certain that event will occur.  

B) If the probability of an event occurring is​ 0, then it is impossible for that event to occur.

We know that the range of probability of an event occurring is in the segment [0, 1]. In statement under (A), we have the probability that  is equal to 1.5.

Therefore, we conclude that the statement in (A) is incorrect.

8 0
3 years ago
Please answer this question now
larisa [96]

Answer:

1471.15

Step-by-step explanation:

4 0
3 years ago
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