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3 years ago

HELP ASAP NEED HELP PLS

Mathematics

1 answer:

Viefleur [7K]3 years ago

5 0

The answer is B i did it yes. Thanks

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Find the product. (-4·3·2)2

d1i1m1o1n [39]

The final product is -24(2) which equals - 48.

6 0

3 years ago

Solve for x. PLZ HELP ASAP!!!

ycow [4]

X is a vertical angle to the angle marked as 100 degrees.

Vertical angles are the same so x = 100 degrees

Answer: 100 degrees

3 0

3 years ago

I believe the answer is B can anyone confirm please?

Marizza181 [45]

The answer is D, not B

7 0

4 years ago

HELP PLEASE!

Mila [183]

Answer:

Option C: The line y = x

Step-by-step explanation:

Let us take an ordered pair (x, y) of a function. Then the ordered pair of its inverse function would be (y, x).

That is to say, when we reflect a point (x, y) across the line y = x we get the point (y, x).

Note that since, this function is invertible, it is both 'one - one' and 'onto'.

6 0

3 years ago

Write a quadratic equation in standard form that has a vertex of (-2, 6) and passes through (-4, -2).

Marizza181 [45]

Answer:

The equation of the quadratic in standard form is:

$y=-2x^2-8x-2$

Step-by-step explanation:

Since they give us the information about where the vertex of the parabola is located, and one extra points where it passes through, we can use the general form of a quadratic in vertex form:

$y-y_v=a\,(x-x_v)^2$

where $(x_v,y_v)$ is the location of the vertex (in our case the point (-2,6).

Therefore the equation above becomes:

$y-y_v=a\,(x-x_v)^2\\y-6=a\,(x-(-2))^2\\y-6=a\,(x+2)^2$

Now,we can use the fact that the point (-4,-2) is also a point of the graph, to find the value of the parameter $"a"$ :

$y-6=a\,(x+2)^2\\-2-6=a\,(-4+2)^2\\-8=a\,(-2)^2\\-8=a\,*4\\a=-2$

Then, the equation of the quadratic with such characteristics becomes:

$y-6=-2\,(x+2)^2\\y-6=-2x^2-8x-8\\y=-2x^2-8x-2$

which is the equation of the quadratic in standard form.

7 0

3 years ago