I will solve your system by substitution.<span><span><span><span>2x</span>+<span>3y</span></span>=2</span>;<span><span>x+<span>6y</span></span>=<span>4x</span></span></span>Step: Solve<span><span><span>2x</span>+<span>3y</span></span>=2</span>for x:<span><span><span><span>2x</span>+<span>3y</span></span>+<span>−<span>3y</span></span></span>=<span>2+<span>−<span>3y</span></span></span></span>(Add -3y to both sides)<span><span>2x</span>=<span><span>−<span>3y</span></span>+2</span></span><span><span><span>2x</span>2</span>=<span><span><span>−<span>3y</span></span>+2</span>2</span></span>(Divide both sides by 2)<span>x=<span><span><span><span>−3</span>2</span>y</span>+1</span></span>Step: Substitute<span><span><span><span>−3</span>2</span>y</span>+1</span>forxin<span><span><span>x+<span>6y</span></span>=<span>4x</span></span>:</span><span><span>x+<span>6y</span></span>=<span>4x</span></span><span><span><span><span><span><span>−3</span>2</span>y</span>+1</span>+<span>6y</span></span>=<span>4<span>(<span><span><span><span>−3</span>2</span>y</span>+1</span>)</span></span></span><span><span><span><span>92</span>y</span>+1</span>=<span><span>−<span>6y</span></span>+4</span></span>(Simplify both sides of the equation)<span><span><span><span><span>92</span>y</span>+1</span>+<span>6y</span></span>=<span><span><span>−<span>6y</span></span>+4</span>+<span>6y</span></span></span>(Add 6y to both sides)<span><span><span><span>212</span>y</span>+1</span>=4</span><span><span><span><span><span>212</span>y</span>+1</span>+<span>−1</span></span>=<span>4+<span>−1</span></span></span>(Add -1 to both sides)<span><span><span>212</span>y</span>=3</span><span><span><span><span>212</span>y</span><span>212</span></span>=<span>3<span>212</span></span></span>(Divide both sides by 21/2)<span>y=<span>27</span></span>Step: Substitute<span>27</span>foryin<span><span>x=<span><span><span><span>−3</span>2</span>y</span>+1</span></span>:</span><span>x=<span><span><span><span>−3</span>2</span>y</span>+1</span></span><span>x=<span><span><span><span>−3</span>2</span><span>(<span>27</span>)</span></span>+1</span></span><span>x=<span>47</span></span>(Simplify both sides of the equation)Answer:<span><span>x=<span><span><span>4/7</span><span> and </span></span>y</span></span>=<span>2/<span>7
is what i got sorry if it don't help</span></span></span>
The value of the population of the growth of an endangered birth after 5 years is 1975
<h3>How to determine the population after 5 years?</h3>
The population function is given as:
B(t) = 100 + 3/5t^5
At 5 years, the value of t is 5
So, we have
t = 5
Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5
This gives
B(5) = 100 + 3/5 * 5^5
Evaluate the exponent
B(5) = 100 + 3/5 * 3125
Evaluate the product
B(5) = 100 + 1875
Evaluate the sum
B(5) = 1975
Hence, the value of the population of the growth of an endangered birth after 5 years is 1975
Read more about exponential functions at:
brainly.com/question/2456547
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Answer:
1/2 - 3(1/2 + 1)²
simplify the expression (1/2 + 1)
1/2 - 3•(3/2)²
using PEMDAS, we see we have to evaluate the exponent first
(3/2)² = 9/4
rewrite the equation
1/2 - 3 • (9/4)
multiply 3 by (9/4)
1/2 - (27/4)
subtract
-25/4
(1 + 1/3)² - 2/9
simplify the expression (1 + 1/3)
(4/3)² - 2/9
using PEMDAS, we see we have to evaluate the exponent first
(4/3)² = 16/9
rewrite the equation
(16/9) - (2/9)
subtract
14/9
Let t be the number of tolls they crossed.
Amount they spent at each toll = $1.75.
Amount they spent at gas station = $28.
Let C be the total amount they spent on gas and tolls.
If they crossed 1 toll, then
C = 28 + 1.75(1).
If they crossed 3 tolls, then,
C = 28 + 1.75(3)
If they crossed t tolls, then,
C = 28 + 1.75t
Here, the terms are 28 and 1.75t and the factors are 1.75 and t.
