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emmasim [6.3K]
3 years ago
5

Solve for n round to the tenths place 14/21.2= n\15

Mathematics
1 answer:
algol133 years ago
5 0
Well.... first lets break this problem up. and work on the left side first 
soo we solve this ↓
14/21.2 = 0.66
now lets plug in our values. The left side will just be replaced by 0.66
Soooo
0.66 = n/15 
so this means we do the opposite on both sides of what n and 15 are doing
In this case they are dividing so yes we are doing the opposite by multiply.
sooooo
0.66 = n/15
 ×15 = x 15 they cancel out on the right hand side and lets solver for the left side.
0.66 x 15 = 9.9 
so that means 
n = 9.9
or we could round it and just say 10
n = 10 
hope this helps:P
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Each year, more than 2 million people in the United States become infected with bacteria that are resistant to antibiotics. In p
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A)

<u><em>Null hypothesis:H₀:-</em></u><em> There is no significant difference between in drug resistance between the two states</em>

<u><em>Alternative Hypothesis :H₁:</em></u>

<em>There is  significant difference between in drug resistance between the two states</em>

<em>B)</em>

<em>The calculated value Z =  2.7261 > 2.054 at 0.02 level of significance</em>

<em> Rejected H₀</em>

<em>There is a significant difference in drug resistance between the two states.</em>

C)

P - value = 0.0066

<em>P - value = 0.0066 < 0.02</em>

<em>D) </em>

<em>1) Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given first sample size n₁ = 174</em>

Suppose that, of 174 cases tested in a certain state, 11 were found to be drug-resistant.

<em>First sample proportion </em>

                    p_{1} = \frac{x_{1} }{n_{1} } = \frac{11}{174} = 0.0632

<em>Given second sample size n₂ = 375</em>

Given data  Suppose also that, of 375 cases tested in another state, 7 were found to be drug-resistant

<em>Second sample proportion</em>

<em>                  </em>p_{2} = \frac{x_{2} }{n_{2} } = \frac{7}{375} = 0.0186<em></em>

<u><em>Step(ii):-</em></u>

<u><em>Null hypothesis:H₀:-</em></u><em> There is no significant difference between in drug resistance between the two states</em>

<u><em>Alternative Hypothesis :H₁:</em></u>

<em>There is  significant difference between in drug resistance between the two states</em>

<em>Test statistic</em>

<em>           </em>Z = \frac{p_{1}-p_{2}  }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }<em></em>

<em>        Where </em>

<em>         </em>P = \frac{n_{1}p_{1} +n_{2} p_{2}  }{n_{1} +n_{2} }<em></em>

<em>        </em>P = \frac{174 (0.0632) + 375 (0.0186) }{174+375 } =  \frac{17.9718}{549} = 0.0327<em></em>

<em>       Q = 1 - P = 1 - 0.0327 = 0.9673</em>

<u><em>Step(iii):-</em></u>

<em></em>

<em>  Test statistic</em>

<em>           </em>Z = \frac{p_{1}-p_{2}  }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }<em></em>

<em>          </em>Z = \frac{0.0632-0.0186  }{\sqrt{0.0327 X 0.9673(\frac{1}{174 }+\frac{1}{375 } ) } }<em></em>

<em>       Z  =   2.7261</em>

<em>   </em>

<em>Level of significance = 0.02 or 0.98</em>

<em>The z-value = 2.054</em>

<em>The calculated value Z =  2.7261 > 2.054 at 0.02 level of significance</em>

<em>    Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

 <u><em>P- value </em></u>

<em>P( Z > 2.7261) = 1 - P( Z < 2.726)</em>

<em>                         = 1 - ( 0.5 + A (2.72))</em>

<em>                         = 0.5 - 0.4967</em>

<em>                          = 0.0033</em>

we will use two tailed test

<em>2 P( Z > 2.7261)  = 2 × 0.0033</em>

<em>                            = 0.0066</em>

<em>P - value = 0.0066 < 0.02</em>

<em>  Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

8 0
3 years ago
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