Question

I need help.................................

Answer 1

Answer:

Option (C)

Step-by-step explanation:

AB and BC are perpendicular to each other at point B.

Ordered pairs representing points A and B are (-3, -1) and (4, 4)

Slope of AB, $(m_1) = \frac{y_2-y_1}{x_2-x_1}$

                             $=\frac{(4+1)}{4+3}$

                             $=\frac{5}{7}$

Let the slope of perpendicular line BC = $m_2$

By the property of perpendicular lines,

$m_1\times m_2=-1$

$\frac{5}{7}\times m_2=-1$

$m_2=-\frac{7}{5}$

Equation of line BC → y - y' = m₂(x - x')

$y-4=(-\frac{7}{5})(x-4)$

y = $-\frac{7}{5}x+\frac{28}{5}+4$

5y = -7x + 28 + 20

7x + 5y = 48

-7x - 5y = -48

Option (C) will be the answer.