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3 years ago

The perimeter of a rectangle garden is 348 feet if the length of the garden is 93 feet what is the width?

Mathematics

2 answers:

Anna11 [10]3 years ago

8 0

The width would be 81 feet.

To find this answer, you could use the expression w = P/2 - l (or l = P/2 - w if you're finding the length)

w = width (93 feet)

and

P = perimeter (348 feet)

Then you divide the perimeter by 2:

348/2 =

174

Lastly you subtract 93 from 174:

174 - 93 =

Then you get your answer :D

I hoped this helped! :)

Ber [7]3 years ago

3 0

The width is 81 feet.
93(2)+81(2)=348

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Answer:

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Step-by-step explanation:

40 and 2x are vertical angles, so they're equal to each other.

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2 years ago

What is true about AngleQRT? Select two options.

stiv31 [10]

The complete question is

"Triangle QST is isosceles, and Line segment R T bisects AngleT. Triangle Q S T is cut by bisector R T. The lengths of sides S T and Q T are congruent. Line segments S R and R Q are congruent. Angles S T R and R T Q are congruent. What is true about AngleQRT?

Select two options. Measure of angleQRT = 90° Measure of angleQRT = Measure of angleSRT AngleQRT Is-congruent-to AngleSTQ Measure of angleQRT = 2*Measure of angleRTQ AngleQRT Is-congruent-to AngleRTQ"

The true about AngleQRT options are A abd B; ∠QRT = 90 and ∠QRT = ∠SRT

<h3>What is the congruent triangle?</h3>

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

Given information;

The triangle QST is isosceles with QT ≅ ST.

The ∠STR and ∠RTQ are congruent.

Now, consider two triangles ∠QTR and ∠STR

In the following triangle

TR ≅ TR

QTR ≅ STR

QT ≅ ST

Now, according to SAS rule, two congruent triangles have congruent corresponding to their sides,

1. QR ≅ SR

2. QRT ≅ SRT

Since the above two angles are congruent so, they will have the same measure

That will be 90 degree.

Hence, The correct options are; ∠QRT = 90 and ∠QRT = ∠SRT

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2 years ago

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3 years ago

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3 years ago

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Find the average value of f over the region D. f(x, y) = 3xy, D is the triangle with vertices (0, 0), (1, 0), and (1, 9)

MakcuM [25]

The average value of f over the region D is 243/4

To answer the question, we need to know what the average value of a function is

<h3>What is the average value of a function?</h3>

The average value of a function f(x) over an interval [a,b] is given by

$\frac{1}{b - a} \int\limits^b_a {f(x)} \, dx$

Now, given that we require the average value of f(x,y) = 3xy over the region D where D is the triangle with vertices (0, 0), (1, 0), and (1, 9).

x is intergrated from x = 0 to 1 and the interval is [0,1] and y is integrated from y = 0 to y = 9

So, $\frac{1}{b - a} \int\limits^b_a {f(x,y)} \, dA = \frac{1}{1 - 0} \int\limits^1_0 \int\limits^9_0 {3xy} \, dxdy \\= \frac{3}{1} \int\limits^1_0 {x} \,dx\int\limits^9_0 {y} \,dy\\ = \frac{3}{1} [\frac{x^{2} }{2} ]^{1}_{0}[\frac{y^{2} }{2} ]^{9}_{0} \\= 3[\frac{1^{2} }{2} - \frac{0^{2}}{2} ] [\frac{9^{2} }{2} - \frac{0^{2}}{2} ] \\= 3[\frac{1}{2} - 0 ][\frac{81}{2} - 0 ]\\= \frac{81}{2} X3 X \frac{1}{2} \\= \frac{243}{4}$

So, the average value of f over the region D is 243/4

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