Question

Find the area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13.

Answer 1

The trapezoid has two right triangles each with one side of length (13-9)2 = 4/2 = 2.

The other side of each right triangle is such that tan 60° = Heigth / 2

Then height = 2*tan60°.

The area of the trapezoid is height * (base 1 + base 2)/2

Then area = 2*tan (60°) * (13+9)/2 = 38.11