Answer:
f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. ... When written in "vertex form": • (h, k) is the vertex of the parabola, and x = h is the axis of symmetry.
To solve this problem, you must follow the proccedure below:
1. T<span>he block was cube-shaped with side lengths of 9 inches and to calculate its volume (V1), you must apply the following formula:
V1=s</span>³
<span>
s is the side of the cube (s=9)
2. Therefore, you have:
V1=s</span>³
V1=(9 inches)³
V1=729 inches³
<span>
3. The lengths of the sides of the hole is 3 inches. Therefore, you must calculate its volume (V2) by applying the formula for calculate the volume of a rectangular prism:
V2=LxWxH
L is the length (L=3 inches).
W is the width (W=3 inches).
H is the heigth (H=9 inches).
4. Therefore, you have:
V2=(3 inches)(3 inches)(9 inches)
V2=81 inches
</span><span>
5. The amount of wood that was left after the hole was cut out, is:
</span>
Vt=V1-V2
Vt=648 inches³
Answer:
A dependent variable
Step-by-step explanation:
is a variable whose value will change depending on the value of another variable, called the independent variable. Dependent variables are also known as outcome variables, left-hand-side variables, or response variables.
Answer:
144
Step-by-step explanation:
On this shape we are going to splt up the 4 triangles for the square to make it simple.
So, firstly, plug is the h an w of one of the triangles into the formula for the area of a triangle which is hxw/2
H=9
W=6
9x6/2=27
Then multiply the area of the triangle, 27, to get the total area of all 4 triangles (since they all have the same measurements)
27x4=108
108 is the area of all 4 triangles
Next, just put the l and w into the equation for the area of a square which is lxw
L=6
W=6
6x6=36
36 is the area of the square
Lastly, just add the areas of the triangles and the square together
108+36=144
144 is the total area/surface area, of the pyramid
Answer:
There are many points that are solutions to the equation, but one of which would be (1, 2)
Step-by-step explanation:
In order to tell if they are a solution, we use the values in the inequality and see if it results in a true statement.
y < -1/2x + 2
1 < -1/2(1) + 2
1 < -1/2 + 2
1 < 3/2 (This is a true statement)
Since it is a true statement, we know it is a solution.
