Question

Find the value of x of the given right triangle.​

Answer 1

Answer:

In the right triangle, the side a=$4$ and the hypotenuse c=$7$.

To find: the value of x

We have,

$a=6$ and $c=7$

Now,by the pythagorean theorem,

${a}^{2} + {b}^{2} = {c}^{2}$

Substitute the values,

${6}^{2} + {x}^{2} = {7}^{2}$

$36 + {x}^{2} = 49$

Subtract 36 from each sides,

${x}^{2} = 13$

Take square root from each sides,

$x = \sqrt{13}$

Hence, the value of x is $\sqrt{13}$.