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LuckyWell [14K]
3 years ago
12

Express it in slope-intercept form.

Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Answer:

y = \frac{2}{3}x + 1

Step-by-step explanation:

Slope-intercept form is y = mx + b where m is the slope and b is the y-intercept. We can see that the y-int. is 1, since that's where the line hits the y-axis. For slope, use \frac{rise}{run}. To hit a point right above a whole number, you would have to go up for and left three, hence \frac{2}{3}. Put that together and get y = \frac{2}{3}x + 1.

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Simplify: 9(a + b) + 4(3a + 2b)<br> A) 13a 13b <br> B) 21a + 17b <br> C) 21a + 2b <br> D) 38ab
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sladkih [1.3K]

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In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is t =
const2013 [10]

Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.

<h3>What is the hang time equation?</h3>

The hang-time of the ball for a player of jump h is given by:

t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}

The expression can be simplified as:

t = 2\sqrt{\frac{h}{16}}

For a player that has a hang time of 0.9s, the jump is found as follows:

0.9 = 2\sqrt{\frac{h}{16}}

\sqrt{\frac{h}{16}} = \frac{0.9}{2}

(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2

h = 16\left(\frac{0.9}{2}\right)^2

h = 3.24 feet.

For a player that has a hang time of 0.8s, the jump is found as follows:

0.8 = 2\sqrt{\frac{h}{16}}

\sqrt{\frac{h}{16}} = \frac{0.8}{2}

(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2

h = 16\left(\frac{0.8}{2}\right)^2

h = 2.56 feet.

The difference is given by:

3.24 - 2.56 = 0.68 feet.

More can be learned about equations at brainly.com/question/25537936

#SPJ1

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2 years ago
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