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3 years ago

Express it in slope-intercept form.

Mathematics

1 answer:

Greeley [361]3 years ago

3 0

Answer:

$y = \frac{2}{3}x + 1$

Step-by-step explanation:

Slope-intercept form is y = mx + b where m is the slope and b is the y-intercept. We can see that the y-int. is 1, since that's where the line hits the y-axis. For slope, use $\frac{rise}{run}$ . To hit a point right above a whole number, you would have to go up for and left three, hence $\frac{2}{3}$ . Put that together and get $y = \frac{2}{3}x + 1$ .

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Identify the variables, the constant, the coefficients, and the exponents in the algebraic

Naya [18.7K]

Variables: x and y
Coefficients: 5 and 2
Constants: 4
Exponents: 2 (if 3y is being squared)

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3 years ago

Which is greater pls help 108.505 108.5? pls help!!

Citrus2011 [14]

Answer:

108.505

Step-by-step explanation:

Let's talk money for just a second. Which would you rather have 20 dollars or 20.32 20dollars and 32 cents?

Isn't 20.32 bigger than 20.

You should say yes.

If that is true, then 108.505 should be larger than 108.5 not by much, but still larger.

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3 years ago

What is the value of -3 +4.5 - (-1.2)?

Mashutka [201]

I believe the answer is 2.7.

Hope the helps!!!

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3 years ago

Which expression gives the distance between the points (5. 1) and (9, -6)?

tresset_1 [31]

D^2=(x2-x1)^2+(y2-y1)^2

8 0

3 years ago

I don't know how to do this or what i'm doing plz help

mote1985 [20]

recalling that d = rt, distance = rate * time.

we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?

$\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}$

so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.

$\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}$

$\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}$

7 0

3 years ago