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nlexa [21]
3 years ago
7

Help? I’m stuck anyone ?

Mathematics
2 answers:
laiz [17]3 years ago
8 0
The answer is B. (-:
ivolga24 [154]3 years ago
7 0
Its B.. Hope that helps :)
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Solve for f.<br><br> 8 = 2f + 2
tiny-mole [99]

Answer:

f = 3

Step-by-step explanation:

8 = 2f + 2

-2         -2

6 = 2f

/2    /2

3 = f

5 0
3 years ago
What is the solution to –2(8x – 4) &lt; 2x + 5?
zhuklara [117]

the answer is x > 1/6

7 0
3 years ago
Subtract. Use models if needed.<br><br><br> (12x + 3) – (2x + 10)
Galina-37 [17]
1.)combine like terms: 12-2x=10x 3-10=-7

10x-7
4 0
3 years ago
Read 2 more answers
F(x)=-3x-5 and g(x) =4x-2 find (f-g)(x)
Triss [41]
<span>F(x)=-3x-5 and g(x) =4x-2 find (f-g)(x)

</span>(f-g)(x) = -3x-5 - (4x-2)
(f-g)(x) = -3x -5 -4x + 2
(f-g)(x) = -7x -3

hope that helps
3 0
3 years ago
There are 4 red and 6 green marbles in a jar. What is the probability of drawing two green marbles, with replacement?
jeka57 [31]

Answer:

\frac{9}{25}

Step-by-step explanation:

Number of red balls = 4

Number of green balls = 6

Total number of balls = 6+4 =10

Probability of drawing a green marble is given as

⇒ \frac{Number\ of\ green\ balls}{Total\ number\ of\ balls}

⇒ \frac{6}{10}

The ball is replaced after drawing.

Probability of drawing a green ball a second time will be:

⇒ \frac{Number\ of\ green\ balls}{Total\ number\ of\ balls}

⇒ \frac{6}{10}

Thus, probability of drawing 2 green balls with replacement can be given as:

⇒  (Probability of drawing a green marble) \times (Probability of drawing a green ball a second time)

⇒ \frac{6}{10}\times\frac{6}{10}

⇒ \frac{36}{100}

Simplifying fraction by dividing numerator and denominator by their GCF.

⇒ \frac{36\div 4}{100\div 4}

⇒ \frac{9}{25} (Answer)

8 0
3 years ago
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