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3 years ago

Sally is taking a test

2 answers:

7 0

Answer: There were 20 questions and she missed three.

First of all, you need to simplify 85/100.

85/100 / 5/5 = 17/20.

Now that you know how many questions were on the test, subtract 17 from 20.

20 - 17 = 3

So in conclusion, the test had 20 questions and she missed three.

But this question doesn’t have enough info to be honest, if you multiply 17/20 with any number it’s still going to be 85%.

miskamm [114]3 years ago

6 0

Answer:

There was 20 questions on the test.

She got 3 wrong.

Step-by-step explanation:

$\frac{85}{100} = \frac{17}{20}$

20 - 17 = 3

There was 20 questions on the test.

She got 3 wrong.

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Solve for y.<br> 72/y=3<br> simplify

Lera25 [3.4K]

Answer:

the answer is 24

Step-by-step explanation:

72/y=3

72/3

8 0

3 years ago

Jade is thinking of a number. 3/4 of 200 is the same as 1/8 of her number. What number is she thinking of?

lorasvet [3.4K]

Answer:

1200

Step-by-step explanation:

3/4 of 200 = 150

150 is 1/8 of 1200

5 0

3 years ago

Read 2 more answers

Helen's house is located on a rectangular lot that is1 1-8 miles by 9/10 mile.Estimate the distance around the lot

klemol [59]

Answer: The distance around the lot is given by

$4\frac{1}{20}\ miles$

Step-by-step explanation:

Since we have given that

Length of rectangular lot is given by

$1\frac{1}{8}\\\\=\frac{9}{8}\ miles$

Width of rectangular lot is given by

$\frac{9}{10}\ mile$

We need to find the distance around the lot.

As we know the formula for "Perimeter of rectangle":

$Perimeter=2(Length+Width)\\\\Perimeter=2(\frac{9}{8}+\frac{9}{10})\\\\Perimeter=2(\frac{45+36}{40})\\\\Perimeter=2\times \frac{81}{40}\\\\Perimeter=\frac{81}{20}\\\\Perimeter=4\frac{1}{20}\ miles$

Hence, the distance around the lot is given by

$4\frac{1}{20}\ miles$

3 0

3 years ago

Read 2 more answers

The length of a rectangular piece of land is 9 cm more than 3 times its width. The perimeter is 418 cm. Find its dimensions.

SashulF [63]

Let w represent the width of the rectangle in cm. Then its length in cm is (3w+9). The perimeter is the sum of two lengths and two widths, so is ...

... 418 = 2(w + (3w+9))

... 209 = 4w +9 . . . . . . divide by 2, collect terms

... 200 = 4w . . . . . . . . subtract 9

... 50 = w . . . . . . . . . . divide by 4

... length = 3w+9 = 3·50 +9 = 159

The dimensions of this piece of land are 159 cm by 50 cm.

3 0

3 years ago

Question 1(Multiple Choice Worth 3 points)

frez [133]

Answer: D) 99 Points

Step-by-step explanation: Theresa earned scores of 88 points, 84 points, 88 points, and 91 points on four tests

Therefore the totals points are 351

351 is her total score for 4 tests, if she gets an average score of 90 on her fifth test then all we have to do is:

5 x 90 = 450 (The 5 being her fifth test)

450-351 = 99

Option D

3 0

3 years ago