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myrzilka [38]
2 years ago
6

If x-1/3=k and k=3 what is the value of x

Mathematics
1 answer:
satela [25.4K]2 years ago
8 0

Answer:

x=10/3

Step-by-step explanation:

hope that helps

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7910 divided by 14. Use a table
zheka24 [161]
Answer to math problem 7910 divided by 14 long division ? Math answers to fraction 7910/14 can be calculated as follows. 7910/14 math problems division = 565. 565 to 2 decimal places= 565 7910/14 divided by 2 » (7910/14) ÷ 2 » 565 ÷ 2 = 282.5 7910/14 long division below
4 0
3 years ago
Which 2-digit number is equal to the sum of its first digit plus the square of its second digit?
LenaWriter [7]
Let, the two-digit number = xy

It is given that, xy = x + y²

Then, number which obey the rule is 89.

Check: 8 + 9² = 8 + 81 = 89 [ Itself ]

In short, Your Answer would be: 89

Hope this helps!
8 0
3 years ago
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Step-by-step explanation:

4 0
3 years ago
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Tom's toy box is shown below. The toy box is shaped like a rectangular prism: It has 5 wooden faces and is open on the top.
bazaltina [42]

Answer:

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5 0
3 years ago
Aditya's dog routinely eats Aditya's leftovers, which vary seasonally. As a result, his weight fluctuates throughout
wariber [46]

Based on the weight and the model that is given, it should be noted that  W(t) in radians will be W(t) = 0.9cos(2πt/366) + 8.2.

<h3>How to calculate the radian.</h3>

From the information, W(t) = a cos(bt) + d. Firstly, calculate the phase shift, b. At t= 0, the dog is at maximum weight, so the cosine function is also at a maximum. The cosine function is not shifted, so b = 1.

Then calculate d. The dog's average weight is 8.2 kg, so the mid-line d = 8.2. W(t) = a cos t + 8.2. Then calculate a, the dog's maximum weight is 9.1 kg. The deviation from the average is 9.1 kg - 8.2 kg = 0.9 kg. W(t) = 0.9cost  + 8.2

Lastly, calculate t. The period p = 2π/b = 2π/1 = 2π. The conversion factor is 1 da =2π/365 rad. Therefore, the function with t in radians is W(t) = 0.9cos(2πt/365) + 8.2.

Learn more about radians on:

brainly.com/question/12939121

7 0
2 years ago
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